local-variables

问题 I modified some code I found to display a local variable instead of set text inside of a JFrame, but I'm unable to find a way to change the size of the text. I keep reading about frameName.setFont(new Font(____)), but that doesn't seem to be working for the println. How would I modify the text size? Here's my current code. (P.S. I'm new, so I'm sorry that i don't know what I'm talking about.) import java.util.*; import java.io.*; import java.awt.*; import javax.swing.*; import java.time.*;

问题 I'm not sure if this question has been asked before ( searched through SOF and couldn't find an answer) I wrote a LinkedList class and a function to reverse it.The function as follows, struct LinkedList::element* LinkedList::recurrsiveReverseList(element* head){ element* tempList; if(head->next == NULL){ return head; }else{ tempList = recurrsiveReverseList(head->next); head->next->next = head; head->next = NULL; return tempList; } } here I am declaring a local pointer variable and making some

问题 I've been trying to make an encryption and decryption system but I have run into a small error. Here is my code: import sys import pyperclip def copy(data): question = input("Copy to clipboard? ") if question.lower() == 'yes' or question.lower() == 'y': pyperclip.copy(data) print("Encrypted message copied to clipboard.") rerun() elif question.lower() == 'no' or question.lower() == 'n': rerun() else: print("You did not enter a valid input.") copy(data) def rerun(): ask = input("\nWould you

问题 To avoid clobbering existing variables, I have code like this window.x = typeof x != "undefined" ? x : {} Which seems like a very long winded way to define something, but necessary to avoid console errors. I tried this out instead, and it seems to work ok. Is it ok to define a variable like this? window.x=window.x||{} Or even in the global scope... x=this.x||{} 回答1: If you use this construct: window.x=window.x||{} And x is defined but has a falsy value (zero, the empty string, null, NaN,

问题 This question already has answers here : Is there any way to access a local variable in outer scope in C++? (4 answers) Closed 2 years ago . I want to access a local variable of main function in another scope. My goal is to print 20 in cout . How can I do this? How is it possible in C++? int var = 10; int main(int argc, char *argv[]) { int var = 20; // this var { int var = 40; cout << ::var; // I want to print `var` variable in main scope. // But this command print global variable. } return 0

问题 This question already has answers here : Variable used in lambda expression should be final or effectively final (6 answers) Closed last year . I would like to use local variables in lambda functions but I get error: Please see the 1. and 2. points in the code. class Foo { int d = 0; // 1. It compiles, but ugly, 2. doesnt compile public void findMax(List<List<Route>> routeLists) { int d = 0; // 2.Error : Local variable dd defined in an enclosing scope must be final or effectively final

问题 I know that very similar questions have been asked and answered already, I read the ones I was able to locate and still not 100% clear. Considering this code snippet: public static void fooMethod { while(<...>) { .... final int temp = <something>; .... } } No inner classes, nothing else special or unusual. Seems counter-intuitive to me. Does declaring a local variable final in the above sample serve any purpose whatsoever? Do I understand correctly that with or without final here compiler

问题 I don't know exactly how output buffering works but as far as know it stores content into some internal variable. Regarding this, what is the difference of not using output buffering and storing content in my own local variable instead and than echo it at the end of script? Example with output buffering: <?php ob_start(); echo "html page goes here"; ob_end_flush(); ?> And example without using output buffering: <?php $html = "html page goes here"; echo $html; ?> What is the difference? 回答1:

问题 I have a loop in which I calculate a value and add it it a list. So, I do something like that: x = getValue() values.add(x) while (true) { x = getValue(); values.add(x) } I found out that this approach does not work since I add the same instance to the list. In more details, in every cycle of the loop I re-assign a new value to the x and doing so I change values of all elements that were already added to the list (so in the end I get a list of identical elements). To solve this problem I did

问题 When getting a stacktrace as error report from an application that is already deployed, it would be helpful to also get the actual variable values to reconstruct the system's state at the point before the exception was thrown. Is anything like that feasible in Java and how could one do that? Cheers, Max 回答1: I'm pretty sure you cannot get the local variables in the stacktrace as the output is built from instance of StackTraceElement which only contains, the class, the file, the method and the