intervals

RTCP receiver report sending interval

≯℡__Kan透↙ 提交于 2020-01-04 13:39:03
问题 What is the sending interval of RTCP Receiver Report? In RFC 3550 I was only able to find computation the RTCP Transmission Interval for the server. But as a client I have no idea about members and senders (or do I?). So I'm a little bit confuse how to calculate the interval or should I send RTCP RR in periods or should I only send RR packet when SR is received? 回答1: The RTP and RTCP protocols don't make a distinction between client and server. Both are members within the RTP session and both

RTCP receiver report sending interval

混江龙づ霸主 提交于 2020-01-04 13:38:58
问题 What is the sending interval of RTCP Receiver Report? In RFC 3550 I was only able to find computation the RTCP Transmission Interval for the server. But as a client I have no idea about members and senders (or do I?). So I'm a little bit confuse how to calculate the interval or should I send RTCP RR in periods or should I only send RR packet when SR is received? 回答1: The RTP and RTCP protocols don't make a distinction between client and server. Both are members within the RTP session and both

RTCP receiver report sending interval

蓝咒 提交于 2020-01-04 13:38:27
问题 What is the sending interval of RTCP Receiver Report? In RFC 3550 I was only able to find computation the RTCP Transmission Interval for the server. But as a client I have no idea about members and senders (or do I?). So I'm a little bit confuse how to calculate the interval or should I send RTCP RR in periods or should I only send RR packet when SR is received? 回答1: The RTP and RTCP protocols don't make a distinction between client and server. Both are members within the RTP session and both

How to format time intervals in Java?

醉酒当歌 提交于 2020-01-03 19:08:05
问题 I create J2SE application and this application needs to format two times in milliseconds into a string that represents the interval between this two times. long time1 = 1334331041677L; //Fri Apr 13 17:30:41 CEST 2012 long time2 = time1+1000*60*2; //Fri Apr 13 17:32:41 CEST 2012 and I would like to get something like "00:02:00". This would be simple, but I need to format interval which is long from few seconds up to several years - so the library should handle it. Ideally is if this library

How to format time intervals in Java?

做~自己de王妃 提交于 2020-01-03 19:06:09
问题 I create J2SE application and this application needs to format two times in milliseconds into a string that represents the interval between this two times. long time1 = 1334331041677L; //Fri Apr 13 17:30:41 CEST 2012 long time2 = time1+1000*60*2; //Fri Apr 13 17:32:41 CEST 2012 and I would like to get something like "00:02:00". This would be simple, but I need to format interval which is long from few seconds up to several years - so the library should handle it. Ideally is if this library

Subsetting neighboring fileds

梦想与她 提交于 2020-01-03 05:33:17
问题 I am trying to make a conditional subsetting which would include contemporary elements inside window of neighboring areas. For example, given the matrix Dat, where Species (SP), Area (AR) and Time (TM): SP AR TM A 2 2 B 2 2 C 1 4 F 3 2 B 5 3 E 3 2 D 2 1 I 1 4 H 3 2 E 2 4 D 3 5 B 1 2 How can I retrieve all the species co-occurring with species A in the same time, but within neighboring areas (in this case 1 and 3)? The desired output being: SP AR TM A 2 2 B 2 2 F 3 2 H 3 2 B 1 2 This is based

Deconvoluting intervals into position information

筅森魡賤 提交于 2020-01-03 03:24:07
问题 I have fileA in which the information is displayed by intervals - if consecutive positions are assigned the same value, these consecutive values are regrouped into one interval. start end value label 123 78000 0 romeo #value 0 at positions 123 to 77999 included. 78000 78004 56 romeo #value 56 at positions 78000, 78001, 78002 and 78003. 78004 78005 12 romeo #value 12 at position 78004. 78006 78008 21 juliet #value 21 at positions 78006 and 78007. 78008 78056 8 juliet #value 8 at positions

Loop through two arrays deleting overlaps in perl

℡╲_俬逩灬. 提交于 2020-01-02 04:46:51
问题 I have two sets of ranges, represented by [ start, stop ] values. Some of the ranges overlap, meaning that the start of one range is in between the [ start, stop ] of the other range. I'd like to make a new set of ranges that has no such overlap, and also doesn't include any new values in a range. The ranges look like this: @starts @ends 5 108 5 187 44 187 44 229 44 236 64 236 104 236 580 644 632 770 The output that I expect would be this: @starts @ends 5 236 580 770 This is because the first

NSTimer with multiple time intervals in a sequence

自闭症网瘾萝莉.ら 提交于 2020-01-02 04:36:06
问题 Without creating multiple NSTimer instances, how would one achieve an NSTimer to fire a specific or multiple method with different intervals in a sequence. For example method1 (0.3 sec), method2 (0.5), method3 (0.7) and so on. I would appreciate if someone could please share any example code. 回答1: I'm not sure what your final goal is with this but after reading your question I would recommend to try the following way , maybe this is what you'd look for. you should put this code where you

react native count down timer in millisecond

与世无争的帅哥 提交于 2020-01-01 19:37:00
问题 I need a reverse countdown timer that takes the time in seconds and returns in the form of day, hour, minute, second, and milliseconds (up to two digits, zero to 100 milliseconds). My code below has a time difference because of the delay. Also, ten milliseconds occupy a large amount of CPU to call the timer, what could be causing this? componentDidMount(){ // get the timer in second then timer * 100 this.interval = setInterval(() => { if (this.state.timer > 0){ this.setState((prevState)=>({