ifs

批量拷贝某一个目录下的所有指定的文件到另一个指定的目录 ## 比如拷贝视频文件,针对目录下存在空格命名情况,会导致无法处理成功,需要临时使用系统变量的IFS #!/bin/bash old_IFS = $IFS IFS = $( echo -en "\n\b" ) find . -name "*.mp4" | while read filepath do echo "move file to 100036 dir: $filepath " mv -f $filepath ./100036 done # 恢复系统原理的设置 IFS = $old_IFS 基于云端的API服务进行批量处理 ### 比如github上批量删除无效仓库项目 # 在本地新建一个文件repos,逐行贴上对应的一个仓库名称: githubName/repoName,如: xiaokunliu/delRepo1 xiaokunliu/delRepo2 .. . # github上申请对应开发者账户的删除权限token ### 编写脚本完成 #!/bin/bash cat repos | while read repo do echo "delete github for repo: https://api.github.com/repos/ $repo " curl -XDELETE -H

IFS分隔符的使用 data="name, gender,rollno,location" 我们可以使用IFS读取变量中的每一个条目。 oldIFS=$IFS IFS=, #IFS现在被设置为, for item in $data; do echo Item: $item done IFS=$oldIFS 输出如下： Item: name Item: gender Item: rollno Item: location IFS的默认值为空白字符（换行符、制表符或者空格）。 当IFS被设置为逗号时，shell将逗号视为一个定界符，因此变量 $item 在每次迭代中读取由逗号分隔的子串作为变量值。 来源： https://www.cnblogs.com/moox/p/11997832.html

我使用的环境为：Windows10、python3.6、scapy 2.4.0 一、基本知识 Sniff方法定义： sniff(filter= "" ,iface= "any" , prn=function, count=N) filter的规则使用 Berkeley Packet Filter (BPF)语法 iface用来指定要在哪个网络接口上进行抓包（通常不指定即所有网络接口） prn指定回调函数，每当一个符合filter的报文被探测到时，就会执行回调函数，通常使用 lambda 表达式来写回调函数 count指定最多嗅探多少个报文（是指符合filter条件的报文，而非所有报文） filter写法举例： 抓取源地址为 www.baidu.com 的报文： >>> sniff(filter= "ip src www.baidu.com" , iface=ifs, prn= lambda x:x.summary(), count= 3 ) Ether / IP / TCP 14.215 .177 .39 :https > 192.168 .2 .204 : 6593 A / Padding Ether / IP / TCP 14.215 .177 .39 :https > 192.168 .2 .204 : 6593 A / Padding Ether / IP / TCP 14

For educational reasons I have to exploit an C-Code The Programm set the egid first, and then the vulnerability with the system("/usr/bin/..."); Command. So I made an 'usr' executeable in my Home-Directory and set the Path to the Home PATH=$HOME:$PATH And I want to change the IFS Variable in the bash to /: export IFS='/' Unfortunatelly, when i call the C-Programm: my exploit doesn't work Is anybody able to tell me what is wrong? I suppose we are studying at the same university, because I am currently confronted with the same problem. I don't want to give you the whole solution, because that

On my GNU bash, version 4.3.42(1)-release I am doing some tests to answer a question . The idea is to split a : -separated string and and each of its elements into an array. For this, I try to set the IFS to : in the scope of the command, so that the split is automatic and IFS remains untouched: $ myvar="a:b:c" $ IFS=: d=($myvar) $ printf "%s\n" ${d[@]} a b c And apparently IFS remains the same: $ echo $IFS # empty The BASH reference says that: If IFS is unset, the parameters are separated by spaces. If IFS is null, the parameters are joined without intervening separators. However, then I