getline

C++: possible Xcode (Mac) problem. Can't read in numbers from external file using getline()

由 六月ゝ 毕业季﹏ 提交于 2019-12-20 04:15:13
问题 I'm a Mac Xcode (3.2.2) user, working with the GCC 4.2 compiler, fairly inexperienced with C++ and completely ignorant about compilers. I need to read in numbers from an external file and store them in a vector of ints. I wrote code using streams and getline(). I can compile the code and it runs without errors, but there is no output. It works for a friend (non-Mac and non-GCC 4.2 compiler) though. I did some googling and found several posts about a possible compiler (gcc, Apple) issue in

invalid conversion from 'int' to 'char *'

由 一曲冷凌霜 提交于 2019-12-20 04:06:13
问题 I am suppose to write a program that will read from a text file and store what is inside the text file using structures and regroup and print out the information in the text file. But I have encountered problems with getline . I have try to write getline like this getline(infile, info.name) but it doesn't work. I have also include <string> and <cstring> but I still encounter errors like error C2664: 'std::basic_istream<_Elem,_Traits> &std::basic_istream<_Elem,_Traits>::getline(_Elem *,std:

Segmentation fault depending on string length?

由 十年热恋 提交于 2019-12-20 03:50:47
问题 I am writing a program that will read lines from an infile using getline into strings, convert the strings to c-strings containing the first m nonwhitespace characters of the string, then concatenate the c-strings into a single char array. A sample file might look something like this: 5 //number of rows and columns in a grid 2 //number of grids XXXXX XXXXX XXXXX XXXXX XXXXX XXXXX XXXXX XXXXX XXXXX XXXXX So I'd end up with a char array of 2x5x5 characters. Now the problem is my code works fine

C++ Getline after Cin

由 会有一股神秘感。 提交于 2019-12-20 03:34:07
问题 I am trying to write a program which gets user's input in a specific way. First, I input a word which contains no space; Then, I input another word which may contains space; And the program outputs the 2 words separately. For example, I input "Tom a lazy boy" Then the program outputs "Tom:a lazy boy" Here is what I attempted to do: int main(){ string a; cin >> a; string b; getline(cin, b); cout << a << ":" << b<< endl; } I tried using getline after cin, however the output looks like: "Tom: a

Apparently missing overload of getline() taking RRef to stream in GCC 4.7.2 and Clang 3.2

由 拟墨画扇 提交于 2019-12-20 01:33:34
问题 I ran into an unexpected compilation error when trying to use getline() with a temporary stream object: #include <iostream> #include <string> #include <sstream> using namespace std; int main() { string input = "hello\nworld\nof\ndelimiters"; string line; if (getline(stringstream(input), line)) // ERROR! { cout << line << endl; } } It looks like no overload of getline() exists that accepts an rvalue reference to a stream object. If I change main() to use an lvalue, it compiles and runs as

C++ getline函数用法

由 ▼魔方 西西 提交于 2019-12-19 07:04:06
getline()函数是一个比较常见的函数。根据名字直接望文生义，就知道这个函数是来完成读入一行数据。 下面就对C++ -- getline()函数的用法说明，以及getline()函数作为while条件的问题，总结一下： 在C++中本质上有两种getline函数： 第一种：在头文件<istream>中，是iostream类的成员函数。 第二种：在头文件<string>中，是普通函数。 /////////////////////////////////////////////////////////////////////////////////////////// 第一种： 在<istream>中的getline()函数有两种重载形式： istream& getline (char* s, streamsize n ); istream& getline (char* s, streamsize n, char delim ); 作用是： 从istream中读取至多n个字符(包含结束标记符)保存在s对应的数组中。即使还没读够n个字符， 如果遇到delim 或 字数达到限制，则读取终止，delim都不会被保存进s对应的数组中。 *例程代码： #include "stdafx.h" #include <iostream> //使用标准输入流和标准输出流。 // std::cin ;

getline - C++ Reference

由 此生再无相见时 提交于 2019-12-19 07:03:47
getline - C++ Reference std:: getline <string> istream& getline ( istream& is, string& str, char delim ); istream& getline ( istream& is, string& str ); Get line from stream Extracts characters from is and stores them into str until a delimitation character is found. The delimiter character is delim for the first function version, and '\n' (newline character) for the second. The extraction also stops if the end of file is reached in is or if some other error occurs during the input operation. If the delimiter is found, it is extracted and discarded, i.e. it is not stored and the next input

c++: getline

由 主宰稳场 提交于 2019-12-19 07:03:31
(1) istream& getline (istream& is, string& str, char delim); (2) istream& getline (istream& is, string& str); Get line from stream into string Extracts characters from is and stores them into str until the delimitation character delim is found (or the newline character, '\n' , for (2) ). The extraction also stops if the end of file is reached in is or if some other error occurs during the input operation. If the delimiter is found, it is extracted and discarded, i.e. it is not stored and the next input operation will begin after it. return: The same as parameter is . // extract to string

ACM——备忘录

由 泄露秘密 提交于 2019-12-18 23:44:27
getline，cin,(cin>>x).get(); # include <bits/stdc++.h> # include <cstdio> # include <iostream> # include <algorithm> # include <cstring> # include <stdio.h> # include <cmath> # define debug cout<<"ok"<<endl typedef long long ll ; const int maxn = 1e4 + 500 ; const int mod = 1e9 + 7 ; using namespace std ; string s , buf ; int n ; int main ( ) { ios :: sync_with_stdio ( false ) ; ( cin >> n ) . get ( ) ; //cin>>n会忽略掉换行符而getline遇见换行符会停止所以cin不能配getline要用(cin>>n).get();代替 getline ( cin , s ) ; stringstream ss ( s ) ; while ( ss >> buf ) { cout << buf << endl ; } } 来源： CSDN 作者： 蛋蛋さん 链接： https://blog

Use getline and >> when read file C++

由 橙三吉。 提交于 2019-12-18 09:45:02
问题 Because data from file look like this: line 1 is name (first last), next line is score (score1 score 2 ....score5) and so on... So I think that I need getline for name and >> for score Example of data file David Beckham 80 90 100 20 50 Ronaldinho Gaucho 99 80 100 20 60 .... First of all, I have structure struct Player { string name; int score[5]; } player[size] When read data from file int i = 0; while(!file.eof()) { for (int j = 0; j < 2; j++) //read each 2 two lines { if(j==0) // name {
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