divide

python list group by first character

亡梦爱人 提交于 2019-12-06 11:10:54
list1=['hello','hope','hate','hack','bit','basket','code','come','chess'] What I need is: list2=[['hello','hope','hate','hack'],['bit','basket'],['code','come','chess']] If the first character is the same and is the same group, then sublist it. How can I solve this? You can use itertools.groupby : >>> from itertools import groupby >>> list1 = ['hello','hope','hate','hack','bit','basket','code','come','chess'] >>> [list(g) for k, g in groupby(list1, key=lambda x: x[0])] [['hello', 'hope', 'hate', 'hack'], ['bit', 'basket'], ['code', 'come', 'chess']] Expanding on TerryA's answer: To create a

Creating line dividers in Android tab layout paragraphs

人盡茶涼 提交于 2019-12-05 10:28:43
Hey all, first post and a noob in Android programming, but willing to learn! Basically I've taken the Google sample of a tab layout from here I found that method to be very easy to create tabs with text within each tab, but I'm trying to make it so that when a tab is selected, I want the text listed below to be separated by a dividing line. So that a line is dividing between each paragraph, however I'm having trouble doing this. This is what I have so far: main.xml: <?xml version="1.0" encoding="utf-8"?> <TableRow> <TextView android:id="@+id/textview1" android:layout_width="fill_parent"

Split String into groups with specific length

此生再无相见时 提交于 2019-12-05 04:53:27
How can I split the given String in Swift into groups with given length, reading from right to left? For example, I have string 123456789 and group length of 3. The the string should be divided into 3 groups: 123 , 456 , 789 . String 1234567 will be divided into 1 , 234 , 567 So, can you write some nice code in Swift: func splitedString(string: String, length: Int) -> [String] { } BTW tried function split() , but as I understand it works only with finding some symbol Just to add my entry to this very crowded contest ( SwiftStub ): func splitedString(string: String, length: Int) -> [String] {

For loop divide numbers

守給你的承諾、 提交于 2019-12-04 04:19:13
问题 I'm an amateur when it comes to C++ but I've already received a task which is over my knowledge. Task is to enter numbers n,m. Programme must take it as an interval, in which it checks if there is any number which is a sum of numbers with the same exponent. EDIT:(18.10.15) Turns out I didn't understood my task correctly. Here it is: "User enter two numbers. Programme takes it as the interval in which it checks all the numbers. If there's a number in interval which all digit's sum of SAME

Where can I find soft-multiply and divide algorithms?

不想你离开。 提交于 2019-12-03 23:51:46
I'm working on a micro-controller without hardware multiply and divide. I need to cook up software algorithms for these basic operations that are a nice balance of compact size and efficiency. My C compiler port will employ these algos, not the the C developers themselves. My google-fu is so far turning up mostly noise on this topic. Can anyone point me to something informative? I can use add/sub and shift instructions. Table lookup based algos might also work for me, but I'm a bit worried about cramming so much into the compiler's back-end...um, so to speak. Here's a simple multiplication

Divide each data frame row by vector in R

随声附和 提交于 2019-12-03 09:59:40
I'm trying to divide each number within a data frame with 16 columns by a specific number for each column. The numbers are stored as a data frame with 1-16 corresponding to the samples in the larger data frames columns 1-16. There is a single number per column that I need to divide by each number in the larger spreadsheet and print the output to a final spreadsheet. Here's and example of what I'm starting with. The spreadsheet to be divided. X131.478.1 X131.478.2 X131.NSC.1 X131.NSC.2 X166.478.1 X166.478.2 1/2-SBSRNA4 4 2 2 6 7 6 A1BG 93 73 88 86 58 65 A1BG-AS1 123 103 96 128 46 57 The numbers

How to divide a list into n equal parts, python

感情迁移 提交于 2019-12-03 07:28:36
问题 Given ( any ) list of words lst I should divide it into 10 equal parts. x = len(lst)/10 how to give these parts variable names? In the output I need 10 variables ( part1, part2... part10 ) with x number of words in it. 回答1: One-liner returning a list of lists, given a list and the chunk size: >>> lol = lambda lst, sz: [lst[i:i+sz] for i in range(0, len(lst), sz)] Testing: >>> x = range(20, 36) >>> print x [20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35] >>> lol(x, 4) [[20, 21,

How to divide and load a ListView in multiple parts?

被刻印的时光 ゝ 提交于 2019-12-02 05:16:57
问题 I am wondering how could i divide my ListView in parts and display only one part of it when user starts my app and display others when user press a Button called "Load More Items". I have a big list of more than 500 items and thinking to divide it into parts so it could load fast. I want functionality similar to an any email app which gives an option at the bottom to load more emails. If anyone has any sample code for my problem then please share else a little guidance would also be

Grafana dividing 2 series

﹥>﹥吖頭↗ 提交于 2019-12-01 22:25:18
I'm trying to divide 2 series to get their ratio. For example I'm got sites (a.com, b.com, c.com) as * (All sites) Each of them has total sections count and errors occurred stats. I'm wanna to show as bars errors/sections where section > errors for each site to each erros for this site. Here I'm whant to got 3 bars. So: A parser.*.sections.total B parser.*.errors.total X-Axis Mode:Series Display:DrawMode: Bars When i'm trying to use divideSeries I'm always got VallueError (divideSeries second argument must reference exactly 1 series) You can use mapSeries with divideSeries to do vector

Grafana dividing 2 series

南笙酒味 提交于 2019-12-01 19:03:44
问题 I'm trying to divide 2 series to get their ratio. For example I'm got sites (a.com, b.com, c.com) as * (All sites) Each of them has total sections count and errors occurred stats. I'm wanna to show as bars errors/sections where section > errors for each site to each erros for this site. Here I'm whant to got 3 bars. So: A parser.*.sections.total B parser.*.errors.total X-Axis Mode:Series Display:DrawMode: Bars When i'm trying to use divideSeries I'm always got VallueError (divideSeries second