divide

问题 I want to divide the image into sub images and when I click on a part of the image will give me the name of the region, for example, this is my question how to recognize a region from the image, or how to divide the image into sub-images and use it in imageViews And thank you in advance 回答1: In my opinion @fractalwrench's idea is quite good for your case. Basic steps are listed below. Subclass Android ImageView . For example, MultiRegionImageView . Override its onTouchEvent method. (This

问题 I'm new to Python. I'm trying to implement Strassen's Algorithm. The size of the matrix will always be a power of 2 in my implementation. So, how do I divide the matrix into 4 equal sized quadrants? Thanks 回答1: >>> xs = np.arange(16) >>> xs array([ 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15]) >>> xs.reshape(4, 4) array([[ 0, 1, 2, 3], [ 4, 5, 6, 7], [ 8, 9, 10, 11], [12, 13, 14, 15]]) >>> xs = xs.reshape(4, 4) >>> a, b, c, d = xs[:2, :2], xs[2:, :2], xs[:2, 2:], xs[2:, 2:] >>> print

问题 Here I have an example file of multiple objects each measured at the same time-points (also ND.T represents each unique time point). I would like to split this file into separate files (using a python script) containing all objects unique to each time-point still containing the header. Original file: ID ND.T Time [s] Position X [%s] Position Y [%s] Speed [%s] Area [%s] Width [%s] MeanIntensity 1 1 3.87 417.57 11.46 0.06 339.48 14.1 245.65 1 2 8.72 417.37 11.68 0.04 342.61 14.15 239.34 1 3 13

问题 What is the best practice for saving meta information to a dataframe? I know of the following coding practice import pandas as pd df = pd.DataFrame([]) df.currency = 'USD' df.measure = 'Price' df.frequency = 'daily' But as stated in this post Adding meta-information/metadata to pandas DataFrame this is associated with the risk of losing the information by appling functions such as "groupby, pivot, join or loc" as they may return "a new DataFrame without the metadata attached". Is this still

问题 lets say I have 136.181.0.0 /16 and I want to divide it into eleven subnets I got /19? First it was /16 which has only 1 subnet (actually when subnetting is not yet applied, it is still called Network Address). Borrow 1 bit from the host bits, you get /17 with two subnets. Borrow another one then you'll get 4 subnets and a prefix of 18. Borrow another bit then you get 8 subnets with /19 as the CIDR. not sure about 9th,10th and 11th on here.. 1st 136.181.0.0/19 2nd 136.181.32.0/19 3rd 136.181

问题 I have come across a problem. There are N piles of stones where the ith pile has xi stones in it. Alice and Bob play the following game: a. Alice starts, and they alternate turns. b. In a turn, a player can choose any one of the piles of stones and divide the stones in it into any number of unequal piles such that no two of the piles you create should have the same number of stones. For example, if there 8 stones in a pile, it can be divided into one of these set of piles: (1,2,5), (1,3,4),

问题 list1=['hello','hope','hate','hack','bit','basket','code','come','chess'] What I need is: list2=[['hello','hope','hate','hack'],['bit','basket'],['code','come','chess']] If the first character is the same and is the same group, then sublist it. How can I solve this? 回答1: You can use itertools.groupby: >>> from itertools import groupby >>> list1 = ['hello','hope','hate','hack','bit','basket','code','come','chess'] >>> [list(g) for k, g in groupby(list1, key=lambda x: x[0])] [['hello', 'hope',

问题 In SQL Server 2005 Express, the result is below SELECT 100 / 15 --Result 6 But I wanna get approximate value 7 (like using calculator) 100 / 15 = 6.6666.. How to make it in SQL Server? 回答1: You have to use decimal numbers e.g. 100 / 15.0. If you use integers the result is interpreted as an integer and truncated to the largest integer that is smaller than or equal to the result. 回答2: SELECT cast(100 as float) / (15 as float) 回答3: You want SQL Server to perform floating-point divison, as

问题 I wonder how to divide the elements in DataFrame by its line max. See following code: index = pd.date_range('1/1/2000', periods=8) df = DataFrame(np.random.randn(8, 3), index=index, columns=['A', 'B', 'C']) dfMax = df.max(axis=1) and then, the elements in df will be dividedby dfMax based on the same line. Does anyone have an idea? 回答1: I'm pretty sure you can just use df.divide() If df is A B C 2000-01-01 -1.420930 -0.836832 0.941576 2000-01-02 -1.011576 0.297129 0.768809 2000-01-03 0.482838

问题 How can I split the given String in Swift into groups with given length, reading from right to left? For example, I have string 123456789 and group length of 3. The the string should be divided into 3 groups: 123 , 456 , 789 . String 1234567 will be divided into 1 , 234 , 567 So, can you write some nice code in Swift: func splitedString(string: String, length: Int) -> [String] { } BTW tried function split() , but as I understand it works only with finding some symbol 回答1: Just to add my entry