crontrigger

问题 This question already has answers here : How to create a time-driven trigger that runs from 11 am to 2 pm? (2 answers) Closed 2 years ago . I'm trying to schedule an Apps Script function. I need the email to trigger Mon-Sat every 2 hours starting at 11am-9pm. I've written the following code to create triggers for each day: function createTriggers() { var days = [ScriptApp.WeekDay.MONDAY, ScriptApp.WeekDay.TUESDAY, ScriptApp.WeekDay.WEDNESDAY, ScriptApp.WeekDay.THURSDAY, ScriptApp.WeekDay

问题 This question already has answers here : How to create a time-driven trigger that runs from 11 am to 2 pm? (2 answers) Closed 2 years ago . I'm trying to schedule an Apps Script function. I need the email to trigger Mon-Sat every 2 hours starting at 11am-9pm. I've written the following code to create triggers for each day: function createTriggers() { var days = [ScriptApp.WeekDay.MONDAY, ScriptApp.WeekDay.TUESDAY, ScriptApp.WeekDay.WEDNESDAY, ScriptApp.WeekDay.THURSDAY, ScriptApp.WeekDay

问题 This question already has answers here : How to create a time-driven trigger that runs from 11 am to 2 pm? (2 answers) Closed 2 years ago . I'm trying to schedule an Apps Script function. I need the email to trigger Mon-Sat every 2 hours starting at 11am-9pm. I've written the following code to create triggers for each day: function createTriggers() { var days = [ScriptApp.WeekDay.MONDAY, ScriptApp.WeekDay.TUESDAY, ScriptApp.WeekDay.WEDNESDAY, ScriptApp.WeekDay.THURSDAY, ScriptApp.WeekDay

问题 I would like to call a cron job from within a PHP script. I am assuming this is the correct and most efficient solution to my problem. Background: I want to run a script that uses a user's inputted password before I store it in the database with 1 way encryption. I also want to make sure the entire script runs even if the user leaves my site. There are either two possibilities. 1.) Create a two way encrypted password that I can run later in the evening through cron (probably not secure, but

问题 My service api takes in startDate for quartz Job and day of Month for the job to executed. Internally, I convert this to cron expression and save in quartz. For example, a user in PST submits a job request today (Nov 3 2017) as follows. { "start": "2017-11-03T18:00:00-07:00", "dayOfMonth" : 15 } Here the user wants to schedule a job that fires on 15th of each month at 6 PM, starting from 2017-11-03. so the first-day quartz will fire will be 2017-11-15. This is how the above request gets

问题 I have a Scheduler with number of jobs. I want to be able to show all of the active jobs that are in the scheduler, by that I mean that i want to show when each job is triggerd. This is my code: sched.start(); JobDetail job = newJob(Jobs.class) .withIdentity(job_name_, "default") .usingJobData("job_type", job_type_) .build(); Trigger trigger = newTrigger() .withIdentity(job_name_, "default") .startNow() .withSchedule(cronSchedule(date_time_)) .build(); sched.scheduleJob(job, trigger); How can

问题 I want to trigger the second to last day of week of the month. Typically, here is the last friday of the month (ex : 30/06/2017) 0 0 0 ? * FRIL And I want the second to last (ex : 23/06/2017) 0 0 0 ? * FRIL-1 But this syntax return the same result as before (with the Quartz scheduler and with cronmaker) The second to last day of week of the month can appear either the 3rd or the 4th week of the month. So it's : either : 0 0 0 ? * FRI#3 or : 0 0 0 ? * FRI#4 Do you have any advice ? 回答1: I don

问题 I have been trying to come up with a cron expression to start a job at 8.30am and run every 30 mins until midnight and restart at 8.30am next day. I came up with following expression but only thing it lacks is starting at 8.30am. Rather than starting at 8.30 it starts at 8.00. 0 0/30 8/1 * * ? Is it even possible to do what I'm trying to do? I'll be using java quartz2.x.x 回答1: It seems to be not possible in single expression. There is good link, to create your cron expression, you may refer

问题 I have a cronTrigger for a job "digestJob": <bean id="digestCronTrigger" class="org.springframework.scheduling.quartz.CronTriggerBean"> <property name="jobDetail" ref="digestJob" /> <property name="cronExpression" value="0 35 15 * * ?" /> </bean> Here is my schedulerFactoryBean configuration: <bean class="org.springframework.scheduling.quartz.SchedulerFactoryBean"> <property name="triggers"> <list> <ref bean="digestCronTrigger" /> </list> </property> </bean> The problem is, the

问题 I need to run a job on the last day of every month. i tried the following cron expression: <property name="cronExpression" value="0 0 3 L * * *" /> but got this error: Caused by: java.lang.UnsupportedOperationException: Support for specifying both a day-of-week AND a day-of-month parameter is not implemented. it doesnt like the L , but without using it, how can i run on the last day of the month? 回答1: Just change your trigger to 0 0 3 L * ? One of day of week or day of month needs to be ? .