classname

Parsing the HTML content using compound class using selenium python

喜欢而已 提交于 2019-12-02 05:45:10
问题 I am having a display button in my GUI that shows the connection status (Button with Green check means connection is established and with Red cross means no connection) I have to check the status using my code. I am parsing the content of that particular title-bar class name (container-fluid). And from this, I am parsing the explicit content of that display button. elem = driver.find_element_by_class_name("container-fluid") a= elem.get_attribute("outerHTML") b= a.split("powerOn icon-ok-sign")

Parsing the HTML content using compound class using selenium python

末鹿安然 提交于 2019-12-02 00:32:36
I am having a display button in my GUI that shows the connection status (Button with Green check means connection is established and with Red cross means no connection) I have to check the status using my code. I am parsing the content of that particular title-bar class name (container-fluid). And from this, I am parsing the explicit content of that display button. elem = driver.find_element_by_class_name("container-fluid") a= elem.get_attribute("outerHTML") b= a.split("powerOn icon-ok-sign") After this, I parse some explicit content of that button and decide that connection is there or not.

Use duplicate class name on an element?

戏子无情 提交于 2019-12-01 23:24:48
问题 I found that there are many frameworks will check the duplicate class name before adding the new class name on the element that i think will slow down the performance. Is there any problems while the element has duplicate class name? It will also apply the CSS class without conflict while the duplicate class name is in used. <div class="aa bb cc aa"></div> Is it OK to add a class name simply just like elem.className += ' ' + 'aa ee' , even the element has duplicate class name? 回答1: There is

Start Activity Android with class name

a 夏天 提交于 2019-12-01 15:28:50
I am using Following Code to start setting I want to launch the setting activity which is started by android ins PackageList allowedAppsPackageName=CallHelper.Ds.getPackageList(); PackageManager manager = CallDetectService.packageManager; Intent mainIntent = new Intent(Intent.ACTION_MAIN, null); mainIntent.addCategory(Intent.CATEGORY_LAUNCHER); final List<ResolveInfo> apps = manager.queryIntentActivities(mainIntent, 0); Collections.sort(apps, new ResolveInfo.DisplayNameComparator(manager)); final int count = apps.size(); ResolveInfo info=new ResolveInfo();; GridViewAppList.clear(); for (int i

Is it poor form to use CLASS attributes with no corresponding CSS rule? [duplicate]

老子叫甜甜 提交于 2019-12-01 15:16:17
This question already has an answer here: Can I use non existing CSS classes? 13 answers For example if I wanted to select some elements with a certain class using jQuery, and for that reason only, is it always expected that those classes SHOULD be defined in the css?. <div class="xyz"> something </div> <div class="xyz"> something else </div> //with example jQuery $(".xyz").hide(); //is it wrong no element 'xyz' is defined in css? Using CSS classes and - depending on the case - IDs (unique!!) is perfectly fine and often the only solution to keep your HTML code valid while giving additional

className && classList介绍

房东的猫 提交于 2019-12-01 05:35:11
####className #####1.简介 DOM操作中经常会处理元素的样式名,几乎所有的HTML标签中都包含了 class 属性(除了 base , head , html , meta , param , script , style 以及 title 标签),用于规定当前元素的 类名 ,这里的 类名 指的是我们在样式表中按照规则为元素指定的类(class)。如: <style> .big{ font-size:20px; } </style> <p id="page" class="big">内容</p> 也可以为单个元素标签添加多个类,如: <style> .big{ font-size:20px; } .textColor{ color:#EEEEEE; } </style> <p id="page" class="big textColor">内容</p> 注:类名不能以"!"开头。 在javascript中,在获取dom元素后可以通过 className 属性来为其获取或设置样式(在javascript中 class 为保留字,所以使用 className 代替。),如: var p = document.getElementById("page"); // 获取元素样式 console.log(p.className); // 设置元素样式

HTML5 Compliant - Trailing Space in Class Attribute

那年仲夏 提交于 2019-12-01 01:59:09
问题 I know that technically HTML5 is a 'living spec' but I'm wondering if it's compliant to have trailing spaces inside of a class name. I didn't see any reference to this scenario in the spec, but one of my teammates said it was invalid. Maybe I missed something? It'd be a pain to trim those spaces (I'm working inside of a large Java ecom application) and I want to know if it's worth doing for SEO, validation or any other purpose. I get the feeling it's not... haha 回答1: As we can see in the link

object.className or object.getAttribute(“className/class”)?

二次信任 提交于 2019-12-01 01:27:57
问题 Between both those : Javascript function setCss(object, css) { return (object.className = css); } function getCss(object, css) { return object.className; } Or function getCss2(object) { if (object.getAttribute("className")) { return object.getAttribute("className"); } return object.getAttribute("class"); } function setCss2(object, cssclass) { if (object.getAttribute("className")) { return object.setAttribute("className",cssclass); } object.setAttribute("class",cssclass); } HTML <a href="#"

Why does Scala place a dollar sign at the end of class names?

与世无争的帅哥 提交于 2019-11-30 19:36:43
In Scala when you query an object for either its class or its class name, you'll get a rogue dollar sign (" $ ") at the tail end of the printout: object DollarExample { def main(args : Array[String]) : Unit = { printClass() } def printClass() { println(s"The class is ${getClass}") println(s"The class name is ${getClass.getName}") } } This results with: The class is class com.me.myorg.example.DollarExample$ The class name is com.me.myorg.example.DollarExample$ Sure, it's simple enough to manually remove the " $ " at the end, but I'm wondering: Why is it there?; and Is there anyway to "

Association between naming classes and naming their files in python (convention?)

寵の児 提交于 2019-11-30 12:25:00
问题 In python (and some other languages) I have learned, that the name of a class should be written in small letters except for the first letter, which should be a capital letter. Example: class FooBar: ... A class should go in a file, named the same as the class. In this example it would be a file foobar.py . If I want to import the class foo somewhere I have to do this: from foobar import FooBar This convention confuses me a little. My intuition tells me, that if the filename indicates a class,