classname

I'm writing a test app that simulates key presses of another application. For every key press I have to check if the right window/form is shown. So what I do is get the pointer of the window being shown and get it's window title. However, not all the windows/forms shown window titles. So I'm thinking it would be better to get the name of the class instead. How can I get the name of the class? QWidget *pWin = QApplication::activeWindow(); when I try: pWin->className(); to get the name of the class, I'm getting: "error: class QWidget has no member named 'className' " Can somebody show me the

In python (and some other languages) I have learned, that the name of a class should be written in small letters except for the first letter, which should be a capital letter. Example: class FooBar: ... A class should go in a file, named the same as the class. In this example it would be a file foobar.py . If I want to import the class foo somewhere I have to do this: from foobar import FooBar This convention confuses me a little. My intuition tells me, that if the filename indicates a class, than it should be written with the first letter in capitals, too, like FooBar.py . This don't look

I wish to understand if both Class.forName("ClassName") and ClassObject.getClass return runtime instance of the class. Then why on comparing the resulting Class object obtained from the two fetches us a Boolean false(if we compare using == or equals). I also want to know what is the exact use of .class method called on the class name.I have read that it is determined at compile time etc but to what purpose. Won't Class.forName("ClassName") suffice?? Thanks Class.forName loads and initializes the class. obj.getClass() returns the class object loaded into permgen. If the class is loaded by the

If I defined a class: class Blah {}; How can I: std::string const className = /* What do I need to do here? */; assert( className == "Blah" ); I dont think typeid().name() is a good idea since it's compiler implementation specific. Is there anything provided by the C++ standard or Boost? Note: If the class were inherited from Qt's QObject, I could easily use QMetaObject::className() to get the class name. Like this: class Blah { static std::string const className() { return "Blah"; }}; std::string const name = Blah::className(); assert(name == "Blah"); Or this: class Blah {}; template <

In mobile safari, in the course of handling touchmove for an element, I change the className of that element. Unfortunately, the visual change does not occur while the user is scrolling, or until the very end of an inertial scroll. What can I do to get the className to visually take immediately? More: Apparently this isn't limited to className changes, but seemingly any change to the DOM, such as innerHTML and style . This is by design unfortunately. iOS safari will queue up all DOM manipulation until the end of a scroll or gesture. Effectively the DOM is frozen during a scroll. I thought I

I'm working on a project and one requirement is if the 2nd argument for the main method starts with “ / ” (for linux) it should consider it as an absolute path (not a problem), but if it doesn't start with “ / ”, it should get the current working path of the class and append to it the given argument. I can get the class name in several ways: System.getProperty("java.class.path") , new File(".") and getCanonicalPath() , and so on... The problem is, this only gives me the directory in which the packages are stored - i.e. if I have a class stored in " .../project/this/is/package/name ", it would