Parsing the HTML content using compound class using selenium python

问题

I am having a display button in my GUI that shows the connection status (Button with Green check means connection is established and with Red cross means no connection) I have to check the status using my code. I am parsing the content of that particular title-bar class name (container-fluid). And from this, I am parsing the explicit content of that display button.

elem = driver.find_element_by_class_name("container-fluid")
a= elem.get_attribute("outerHTML")
b= a.split("powerOn icon-ok-sign") 

After this, I parse some explicit content of that button and decide that connection is there or not.

But If I use class="powerOn icon-ok-sign", I get error :

Compound class names not permitted

<div class="powerOn icon-ok-sign" data-original-title="Connection" style=" font-size: 2em;" data-toggle="tooltip" title="" data-placement="bottom" ng-class="{&quot;powerOn icon-ok-sign&quot;: titleArea.systemStatus.connection.value, &quot;powerOff icon-remove-sign&quot; : !titleArea.systemStatus.connection.value}"></div>

回答1:

But If I use class="powerOn icon-ok-sign", I get error Compound class names not permitted

Actually selenium doesn't support to locate an element using Compound class name.

You should try using on of then instead as :-

driver.find_element_by_class_name("powerOn")

Or

driver.find_element_by_class_name("icon-ok-sign")

Or best way to use css_selector to locate same element using multiple class name as :-

driver.find_element_by_css_selector(".powerOn.icon-ok-sign")

Reference link :-

• Compound class names are not supported error in WebDriver
• How to avoid Compound Class name error in Page Object?

回答2:

You can use search by CSS Selector instead:

driver.find_element_by_css_selector(".powerOn.icon-ok-sign")

or use one of class names to select your element:

driver.find_element_by_class_name("powerOn")

来源：https://stackoverflow.com/questions/41633896/parsing-the-html-content-using-compound-class-using-selenium-python