break

Prevent xdebug to break at first line of index file

由 北城以北 提交于 2019-11-29 09:16:05
I have xdebug setup with Eclipse PDT. Every time I start a debug session, Eclipse breaks at the first line of my root index.php file. Is it possible to prevent this behavior? Ok I found what the problem was. In Eclipse, I just needed to go in "Windows -> Preferences -> PHP -> Debug" and uncheck "Break at first line". To make it work, I also had to go in "Run > Debug Configurations > PHP Web Application" and unselect "Break at first line" in all the configurations. You might have to restart Eclipse for it to work. This question is orginated from eclipes. But the title took me to this page when

what the difference between break with label and without label in javascript

由 强颜欢笑 提交于 2019-11-29 07:11:52
问题 var num = 0; for(var i = 0; i < 10; i++){ for(var j = 0; j < 10 ; j++){ if(i == 5 && j == 5){ break; } num++; } } console.log(num) In the above code, I expect the result to be 55 but why the result is 95. But why if I added the label, the result become 55? var num = 0; outermost: for(var i = 0; i < 10; i++){ for(var j = 0; j < 10 ; j++){ if(i == 5 && j == 5){ break outermost; } num++; } } console.log(num); 回答1: when used without label, break only break the current loop, in your case the

Immediate exit of 'while' loop in C++ [closed]

由 ≡放荡痞女 提交于 2019-11-29 05:58:18
How do I exit a while loop immediately without going to the end of the block? For example, while (choice != 99) { cin >> choice; if (choice == 99) //Exit here and don't get additional input cin>>gNum; } Any ideas? Use break? while(choice!=99) { cin>>choice; if (choice==99) break; cin>>gNum; } cin >> choice; while(choice!=99) { cin>>gNum; cin >> choice } You don't need a break, in that case. Use break , as such: while(choice!=99) { cin>>choice; if (choice==99) break; //exit here and don't get additional input cin>>gNum; } This works for for loops also, and is the keyword for ending a switch

How do I allow breaking on 'System.NullReferenceException' in VS2010?

由 若如初见. 提交于 2019-11-29 05:40:28
I have a VS 2010 C# .NET 4 project. The issue is that the program is not breaking on 'NullReferenceException' errors during debugging. The output window will display the following: A first chance exception of type 'System.NullReferenceException' occurred in myProgram.exe ...but the debugger will just exit out of the function and continue running the rest of the program. How do I change this behavior so that the debugger will break on these exceptions? Go to Debug -> Exceptions -> Search for NullReferenceException and check the "thrown" checkbox. 来源： https://stackoverflow.com/questions/4475464

Breaking out of a loop from within a function called in that loop

由 ∥☆過路亽．° 提交于 2019-11-29 04:57:15
问题 I'm currently trying to figure out a way to break out of a for loop from within a function called in that loop. I'm aware of the possibility to just have the function return a value and then check against a particular value and then break, but I'd like to do it from within the function directly. This is because I'm using an in-house library for a specific piece of hardware that mandates the function signature of my function to look like this: void foo (int passV, int aVal, long bVal) I'm

break and continue in function

由 孤者浪人 提交于 2019-11-29 03:19:50
问题 def funcA(i): if i%3==0: print "Oh! No!", print i break for i in range(100): funcA(i) print "Pass", print i I know script above won't work. So, how can I write if I need put a function with break or continue into a loop? 回答1: A function cannot cause a break or continue in the code from which it is called. The break/continue has to appear literally inside the loop. Your options are: return a value from funcA and use it to decide whether to break raise an exception in funcA and catch it in the

Break out of proprietary toolbox after a given time

由 别来无恙 提交于 2019-11-29 02:00:25
I am iterating through a large test matrix in MATLAB and calling second-party proprietary software (running in MATLAB) each time. I cannot edit the software source code. Sometimes, the software hangs, so I want to exit it after a certain amount of time and move on to the next iteration. In pseudocode, I'm doing this: for i = 1:n output(i) = proprietary_software(input(i)); end How can I skip to the next iteration (and possibly save output(i)='too_long' ) if the proprietary software is taking too long? You will need to call Matlab from another instance of Matlab. The other instance of Matlab

循环输入1-7的数字得到星期几

由 点点圈 提交于 2019-11-29 00:44:24
1 import java.util.Scanner; 2 public class LianXi{ 3 public static void main(String[] args){ 4 System.out.println("请输入1-7的数字"); 5 Scanner sc = new Scanner(System.in); 6 for(int i=1;i<=7;i++){ 7 int week = sc.nextInt(); 8 switch(week){ 9 case 1: 10 System.out.println("星期一"); 11 break; 12 case 2: 13 System.out.println("星期二"); 14 break; 15 case 3: 16 System.out.println("星期三"); 17 break; 18 case 4: 19 System.out.println("星期四"); 20 break; 21 case 5: 22 System.out.println("星期五"); 23 break; 24 case 6: 25 System.out.println("星期六"); 26 break; 27 case 7: 28 System.out.println("星期天"); 29 break; 30

How to cleanly shut down a console app started with Process.Start?

由 非 Y 不嫁゛ 提交于 2019-11-28 22:40:51
问题 This is looking like an impossible task. Absolutely nothing I've found works. The question is how to cleanly close a console application started with Process.Start that has been started with no console window and without using shell execute: ( ProcessStartInfo.CreateNoWindow = true; ProcessStartInfo.UseShellExecute = false; ). It is given that the application being started will shut down "cleanly" if it receives a ctrl-c or ctrl-break signal, but there seems to be no way to send it one that

什么情况下使用break关键字？ 什么情况下使用Continue关键字？ Java如何声明一个数组？JS如何声明一个数组？如何获取数组长度？ 如何遍历数组？

由 戏子无情 提交于 2019-11-28 22:06:22
什么情况下使用break关键字？什么情况下使用Continue关键字？ Break Break 关键用于终止循环。 示例： 1 2 3 4 5 6 for ( int i = 0 ; i < 10 ; i++) { if (i == 4 ) { break ; //终止循环，后面的循环不再执行 } System.out.println(i); } Continue Continue关键字用于终止本次循环，其它循环继续。 示例： 1 2 3 4 5 6 7 for ( int i = 0 ; i < 10 ; i++) { if (i == 4 ) { continue ; // 本次循环终止，其它循环不受影响 } System.out.println(i); } Java如何声明一个数组？JS如何声明一个数组？如何获取数组长度？ JAVA 声明数组 示例： 1 String[] course; // 声明字符串类型数组 可以声明的同时赋值 1 String[] course = { "Java" , "Spring" , "Redis" , "Linux" }; 声明整型数组 1 int [] numbers = { 5 , 3 , 6 , 2 , 7 , 0 }; JAVAScript 创建数组 创建数组时，先声明数组变量，使用关键字var;数组的值由一对中括号( [] )括起来
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