How do I exit a while
loop immediately without going to the end of the block?
For example,
while (choice != 99)
{
cin >> choice;
if (choice == 99)
//Exit here and don't get additional input
cin>>gNum;
}
Any ideas?
Use break?
while(choice!=99)
{
cin>>choice;
if (choice==99)
break;
cin>>gNum;
}
cin >> choice;
while(choice!=99) {
cin>>gNum;
cin >> choice
}
You don't need a break, in that case.
Use break, as such:
while(choice!=99)
{
cin>>choice;
if (choice==99)
break; //exit here and don't get additional input
cin>>gNum;
}
This works for for loops also, and is the keyword for ending a switch clause. More info here.
break;
.
while(choice!=99)
{
cin>>choice;
if (choice==99)
break;
cin>>gNum;
}
Yes, break will work. However, you may find that many programmers prefer not to use it when possible, rather, use a conditional if statement to perform anything else in the loop (thus, not performing it and exiting the loop cleanly)
Something like this will achieve what you're looking for, without having to use a break.
while(choice!=99) {
cin >> choice;
if (choice != 99) {
cin>>gNum;
}
}
hmm, break
?
while(choice!=99)
{
cin>>choice;
if (choice==99)
exit(0);
cin>>gNum;
}
Trust me, that will exit the loop. If that doesn't work nothing will. Mind, this may not be what you want...
Yah Im pretty sure you just put
break;
right where you want it to exit
like
if (variable == 1)
{
//do something
}
else
{
//exit
break;
}
Try
break;
You should never use a break statement to exit a loop. Of course you can do it, but that doesn't mean you should. It just isn't good programming practice. The more elegant way to exit is the following:
while(choice!=99)
{
cin>>choice;
if (choice==99)
//exit here and don't get additional input
else
cin>>gNum;
}
if choice is 99 there is nothing else to do and the loop terminates.
来源:https://stackoverflow.com/questions/872996/immediate-exit-of-while-loop-in-c