break

break and return in ruby, how do you use them?

江枫思渺然 提交于 2019-11-29 20:28:19
I just asked a question about return and it seems to do the same thing as break. How do you use return, and how do you use break, such as in the actual code that you write to solve the problems that can use these constructs. I can't really post examples because I don't know how to use these so they wouldn't make much sense. Return exits from the entire function. Break exits from the innermost loop. Thus, in a function like so: def testing(target, method) (0..100).each do |x| (0..100).each do |y| puts x*y if x*y == target break if method == "break" return if method == "return" end end end end

loop and a half controlled [closed]

女生的网名这么多〃 提交于 2019-11-29 20:21:44
问题 It's difficult to tell what is being asked here. This question is ambiguous, vague, incomplete, overly broad, or rhetorical and cannot be reasonably answered in its current form. For help clarifying this question so that it can be reopened, visit the help center. Closed 7 years ago . When do we use loop and a half? Also, should someone briefly elaborate how to write its code? 回答1: You use loop-and-a-half to avoid repeating code from outside the loop to the inside. Example: read a; while a !=

switch (xx) { case xx: break ......}

早过忘川 提交于 2019-11-29 18:54:55
switch 跟 if 差不多,当某个固定的变量或者属性会发生变化的时候使用。 注意:每个 case 完都要用 break(在函数中可以用return)终止switch,不然会穿透(当前成立的条件之后的代码(包括下面的case)都会执行) 语法:   switch(变量 | 属性){   case 具体条件:   上面条件成立的执行语句   break;   default:   如果上面的判断都不成立,就默认执行 default 的代码   } 来源: https://www.cnblogs.com/MrZhujl/p/11527020.html

循环

ε祈祈猫儿з 提交于 2019-11-29 17:24:25
作者:Vamei 出处:http://www.cnblogs.com/vamei 欢迎转载,也请保留这段声明。谢谢! for循环 for循环需要预先设定好循环的次数(n),然后执行隶属于for的语句n次。 基本构造是 for 元素 in 序列: statement 举例来说,我们编辑一个叫forDemo.py的文件 for a in [3,4.4,'life']: print a 这个循环就是每次从表[3,4.4,'life'] 中取出一个元素(回忆:表是一种序列),然后将这个元素赋值给a,之后执行隶属于for的操作(print)。 介绍一个新的Python函数range(),来帮助你建立表。 idx = range(5) print idx 可以看到idx是[0,1,2,3,4] 这个函数的功能是新建一个表。这个表的元素都是整数,从0开始,下一个元素比前一个大1, 直到函数中所写的上限 (不包括该上限本身) (关于range(),还有丰富用法,有兴趣可以查阅, Python 3中, range()用法有变化,见评论区) 举例 for a in range(10): print a**2 while循环 while的用法是 while 条件: statement while会不停地循环执行隶属于它的语句,直到条件为假(False) 举例 while i < 10: print i

Should we break the default case in switch statement?

你。 提交于 2019-11-29 17:08:12
问题 Assuming this example code (source): #include <stdio.h> void playgame() { printf( "Play game called" ); } void loadgame() { printf( "Load game called" ); } void playmultiplayer() { printf( "Play multiplayer game called" ); } int main() { int input; printf( "1. Play game\n" ); printf( "2. Load game\n" ); printf( "3. Play multiplayer\n" ); printf( "4. Exit\n" ); printf( "Selection: " ); scanf( "%d", &input ); switch ( input ) { case 1: /* Note the colon, not a semicolon */ playgame(); break;

Website layout “breaks apart” when zooming in or out in browsers + a few other basic css questions

不羁的心 提交于 2019-11-29 13:45:56
问题 I'm pretty much as new to CSS as it gets and what I'm trying to do right now is just design a very simple/basic splash or landing page for a small business. Here is the url for the site: My site Now if you go on any browser, lets say google chrome and you zoom out or in (ctrl -/+) you will notice that the website layout starts to "break apart" in that all my divs just start shifting around. I obviously dont want this, and just want the site to remain the same when people zoom in or out,

List ForEach break

人盡茶涼 提交于 2019-11-29 13:09:55
is there a way to break out of the foreach extension method? The "break" keyword doesn't recognize the extension method as a valid scope to break from. //Doesn't compile Enumerable.Range(0, 10).ToList().ForEach(i => { System.Windows.MessageBox.Show(i.ToString()); if (i > 2)break; }); Edit: removed "linq" from question note the code is just an example to show break not working in the extension method... really what I want is for the user to be able to abort processing a list.. the UI thread has an abort variable and the for loop just breaks when the user hits a cancel button. Right now, I have

Line ChartJS empty / null values doesn't break the line

别说谁变了你拦得住时间么 提交于 2019-11-29 11:42:06
I want to break the line of the chart when values is null or empty, but I can't. Perhaps I miss something? var data = { labels: ["January", "February", "March", "April", "May", "June", "July"], datasets: [ { label: "My First dataset", fillColor: "rgba(220,220,220,0.5)", strokeColor: "rgba(220,220,220,0.8)", highlightFill: "rgba(220,220,220,0.75)", highlightStroke: "rgba(220,220,220,1)", data: [65, null, 80, 81, 56, 55, 40] }, { label: "My Second dataset", fillColor: "rgba(151,187,205,0.5)", strokeColor: "rgba(151,187,205,0.8)", highlightFill: "rgba(151,187,205,0.75)", highlightStroke: "rgba

Breaking out of an outer loop from an inner loop in javascript

爱⌒轻易说出口 提交于 2019-11-29 11:07:29
while(valid){ for(loop through associative array){ if(!valid){ break; } } } I have tried to find a way to break out of the while loop from the if statement. So far, the best method seems to be the goto method that is non-existant in Javascript. What is the best way to cause the if statement to break out of both of the loops it is nested in? Thanks in advance for the help! Depending on what your conditionals are, it should be easy to set the iterator of your for-loop to something that would break it, and set your while condition to false. For example, while(someBoolean){ for(var i = 0; i < size

Why it is a bad practice to use break/continue labels in OOP (e.g. Java, C#)? [closed]

亡梦爱人 提交于 2019-11-29 10:03:28
I was told that using break and continue labels in an OOP language is not OOP programming style. Can you explain in detail why and what is the problem? The trick was with this label word. I meant labeled break/continue. class BreakWithLabelDemo { public static void main(String[] args) { int[][] arrayOfInts = { { 32, 87, 3, 589 }, { 12, 1076, 2000, 8 }, { 622, 127, 77, 955 } }; int searchfor = 12; int i; int j = 0; boolean foundIt = false; search: for (i = 0; i < arrayOfInts.length; i++) { for (j = 0; j < arrayOfInts[i].length; j++) { if (arrayOfInts[i][j] == searchfor) { foundIt = true; break