aggregation

问题 Assuming I have the following DataFrame: +---+--------+---+----+----+ |grp|null_col|ord|col1|col2| +---+--------+---+----+----+ | 1| null| 3|null| 11| | 2| null| 2| xxx| 22| | 1| null| 1| yyy|null| | 2| null| 7|null| 33| | 1| null| 12|null|null| | 2| null| 19|null| 77| | 1| null| 10| s13|null| | 2| null| 11| a23|null| +---+--------+---+----+----+ here is the same sample DF with comments, sorted by grp and ord : scala> df.orderBy("grp", "ord").show +---+--------+---+----+----+ |grp|null_col

问题 I am really new to elasticsearch world. Let's say I have a nested aggregation on two fields : field1 and field2 : { ... aggs: { field1: { terms: { field: 'field1' }, aggs: { field2: { terms: { field: 'field2' } } } } } } This piece of code works perfectly and gives me something like this : aggregations: { field1: { buckets: [{ key: "foo", doc_count: 123456, field2: { buckets: [{ key: "bar", doc_count: 34323 },{ key: "baz", doc_count: 10 },{ key: "foobar", doc_count: 36785 }, ... ] },{ key:

问题 I am really new to elasticsearch world. Let's say I have a nested aggregation on two fields : field1 and field2 : { ... aggs: { field1: { terms: { field: 'field1' }, aggs: { field2: { terms: { field: 'field2' } } } } } } This piece of code works perfectly and gives me something like this : aggregations: { field1: { buckets: [{ key: "foo", doc_count: 123456, field2: { buckets: [{ key: "bar", doc_count: 34323 },{ key: "baz", doc_count: 10 },{ key: "foobar", doc_count: 36785 }, ... ] },{ key:

问题 What I want to achieve: I want my "age" aggregation to not be filtered by the query filter and I want to be able to apply filters to it. So if I start with this query: { "query":{ "filtered":{ "filter":{ "terms":{ "family_name":"Brown" } } //filter_1 } }, "aggs":{ "young_age":{ "filter":{ "range":{ "lt":40, "gt":18 } //filter_2 }, "aggs":{ "age":{ "terms":{ "field":"age" } } } } } } My aggregation "young_age" will be filtered by both filter_1 and filter_2. I don't want my aggregation to be

问题 I am learning core data and particularly working on aggregation. Current what I want to do : count the number of records from the table which is in to-many relationship with inverse relationship on some criteria . Currently I am doing this : NSExpression *ex = [NSExpression expressionForFunction:@"count:" arguments:[NSArray arrayWithObject:[NSExpression expressionForKeyPath:@"ddname"]]]; NSPredicate *pred = [NSPredicate predicateWithFormat:@"ddtype == 'Home'"]; NSExpressionDescription *ed = [

问题 Given the following result set: --------------------------------------------------------- CustomerID Service TransType SubTotal Tax NetTotal --------------------------------------------------------- 106 A CREDIT 12.52 - 12.52 106 A CREDIT 10.07 - 10.07 106 B CREDIT 2.00 - 2.00 106 C REMOTE 5.99 - 5.99 106 C CREDIT 5.99 - 5.99 106 C CREDIT 3.99 0.30 3.69 106 C CREDIT 5.99 0.30 5.69 106 D CREDIT 5.99 - 5.99 --------------------------------------------------------- Note that NetTotal = SubTotal

问题 Design Pattern by Gamma et al said Consider the distinction between object aggregation and acquaintance and how differently they manifest themselves at compile- and run-times. Aggregation implies that one object owns or is responsible for another object. Generally we speak of an object having or being part of another object. Aggregation implies that an aggregate object and its owner have identical lifetimes. Acquaintance implies that an object merely knows of another object. Sometimes

问题 I'm new in Core Data, so i want to write simple fetch request to group result by some field and also a count of another field in that group. so for example i have products table i want to retrieve all grouped products by date and the count of product, the simple query in sql is like SELECT DateRegistered,Count(*) FROM Products Group By DateRegistered 回答1: Your best bet is the very flexible NSFetchedResultsController . You would have a fetch request that simply fetches the Product entity

问题 Closed . This question needs to be more focused. It is not currently accepting answers. Want to improve this question? Update the question so it focuses on one problem only by editing this post. Closed 6 months ago . How is instantiation different from aggregation and from acquaintance? (I have undertood the difference between aggregation and acquaintance, see the quote from the book here) Instantiation and aggregation seem similar to each other. when object A instantiates or aggregate object

问题 What I have in my Component.js are these routes: routes: [ { pattern: "", name: "menu", view: "Menu", targetAggregation: "pages", targetControl: "idAppControl", subroutes: [ { pattern: "Reports", name: "reports", view: "SplitContainer", targetAggregation: "pages", targetControl: "idAppControl", clearTarget: true } ] } ] When I try to access the subroute (URL/#/Reports) the application throws (Chrome): Control idAppControl does not has an aggregation called pages - This is confusing due to the