How to clone a multidimensional array in java? [duplicate]

问题

Edit 2: Below is a code snippet based on DuffyMo\'s response that illustrates how to get around the limitations of cloning for multidimensional arrays using System.arraycopy.

import java.util.Arrays;

public class Randar {
public static int[][] arrayMaster = {{6,1}, {10,1}, {1,1}};
private static int[][] arrayChanges = new int[arrayMaster.length][2];

public Randar () {

}
public static void main(String[] args) {
    arrayChanges[0][0] = 0;
    resetArrays(arrayChanges, arrayMaster);
    arrayChanges[0][0] = 0;

    System.out.format(\"arrayMaster: %s, arrayChanges: %s\", Arrays.deepToString(arrayMaster), Arrays.deepToString(arrayChanges));
}


public static void resetArrays(int[][] arrayChanges, int[][] arrayMaster) {
for (int a=0; a< arrayMaster.length; a++) {
System.arraycopy(arrayMaster[a], 0, arrayChanges[a], 0, arrayMaster[a].length);
}
// arrayChanges = arrayMaster.clone(); will NOT work as expected
}
}

[ORIGINAL QUESTION] What\'s a simple way to (fully) clone a multidimensional array in java? This program illustrates my problem.

import java.util.Arrays;

public class Randar {
public static int[][] arrayMaster = {{6,1}, {10,1}, {1,1}};
static private int[][] arrayChanges = arrayMaster;

public static void main(String[] args) {
    arrayChanges[0][0] = 0;
    resetArrays();

    System.out.format(\"arrayMaster: %s, arrayChanges: %s\",Arrays.deepToString(arrayMaster), Arrays.deepToString(arrayChanges));
}


public static void resetArrays() {
arrayChanges = arrayMaster.clone();
}

}

When the above code is run, arrayMaster changes as well as arrayChanges, contrary to my intentions. Thinking that I could clone each single dimensional array member of arrayMaster, I tried to get around the problem with this:

for (int iter = 0; iter < arrayMaster.length; iter++) {
    arrayChanges[iter] = arrayMaster[iter].clone();
    }

but when I run the code that gives a NullPointerException for some reason. Is writing a method that loops through the individual integer values of the arrays my only option?

Thanks.

EDIT 1: This doesn\'t fix the problem either.

import java.util.Arrays;

public class Randar {
public int[][] arrayMaster = {{6,1}, {10,1}, {1,1}};
private int[][] arrayChanges = arrayMaster.clone();

public Randar () {

}
public static void main(String[] args) {
    Randar Randar1 = new Randar();
    Randar1.arrayChanges[0][0] = 0;
    resetArrays(Randar1.arrayChanges, Randar1.arrayMaster);
    Randar1.arrayChanges[0][0] = 0;

    System.out.format(\"arrayMaster: %s, arrayChanges: %s\",     Arrays.deepToString(Randar1.arrayMaster), Arrays.deepToString(Randar1.arrayChanges));
}


public static void resetArrays(int[][] arrayChanges, int[][] arrayMaster) {
/*for (int a=0; a< arrayMaster.length; a++) {
System.arraycopy(arrayMaster[a].clone(), 0, arrayChanges[a], 0, arrayMaster[a].length);
} */
arrayChanges = arrayMaster.clone();
}
}

回答1:

When the above code is run, arrayMaster changes as well as arrayChanges, contrary to my intentions.

The line

static private int[][] arrayChanges = arrayMaster;

is the culprit. This line makes arrayChanges and arrayMaster point to the same object, so a change to either one is visible when you access the object from either.

EDIT: What happens whenever you clone one dimension of a multidimensional array

As Eric Lippert explains, an array is conceptually a list of variables. If you just assign another variable to point to the same array a la static private int[][] arrayChanges = arrayMaster;, you haven't changed the set of variables at all. You haven't created any new variables except for arrayChanges, so you haven't gotten more memory from the operating system/JVM, so any change you make to arrayMaster is applied to arrayChanges and vice versa.

Now let's look at a two-dimensional array. In Java, a two-dimensional array is a list of variables that happens to have the property that each one of these variables refers to a one-dimensional array. So, whenever you clone a two-dimensional array, you create a new list of variables, each pointing in the same place that the old variables pointed in. So, you have gained a little in that you can safely write arrayChanges[0] = new int[10] without affecting arrayMaster, but as soon as you start referencing arrayChanges[i][j] you are still referencing the same second-level arrays that arrayMaster references. What you really want in order to deep-copy a two-dimensional array of ints is

public static int[][] deepCopyIntMatrix(int[][] input) {
    if (input == null)
        return null;
    int[][] result = new int[input.length][];
    for (int r = 0; r < input.length; r++) {
        result[r] = input[r].clone();
    }
    return result;
}

To those who may look at this answer in the future: yes, it is better replace int with T here and make the method generic, but for this purpose a more concrete deep copy method is simpler to explain well.

回答2:

clone does a "shallow" copy. That is, the outermost array is duplicated, but the values stored in it are unchanged. So if you have A1 = { B1, B2, B3 } and clone that into A2, A2's initial contents will be { B1, B2, B3 }. If you change A1 to { C1, B2, B3 } then A2 will remain unchanged, but if you change the contents of B1 (without replacing it) then A2 will "see" that change.

To accomplish what you want you must loop through the outer array and clone the elements of that outer array (which are the inner arrays).

Pidgin Java:

int[][] A2 = A1.clone();
for (int i = 0; i < A2.length; i++) {
    A2[i] = A2[i].clone();
}

来源：https://stackoverflow.com/questions/9106131/how-to-clone-a-multidimensional-array-in-java

标签

java

arrays

cloning