Starting a Jar file using System.Diagnostics.Process

非 Y 不嫁゛ 提交于 2019-12-01 00:00:58

Finally solved it. The filename has to be java and the arguments has to contain the location of the jar file (and anything arguments you want to pass that)

System.Diagnostics.Process clientProcess = new Process();
clientProcess.StartInfo.FileName = "java";
clientProcess.StartInfo.Arguments = @"-jar "+ jarPath +" " + argumentsFortheJarFile;
clientProcess.Start();
clientProcess.WaitForExit();   
int code = clientProcess.ExitCode != 0)

You need to set environment variable Path of java.exe executable or specify the full path of java.exe.

 ProcessStartInfo ps = new ProcessStartInfo(@"c:\Program Files\java\jdk1.7.0\bin\java.exe",@"-jar C:\Users\Owner\Desktop\myJarFile.jar");
 Process.Start(ps);
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