This question already has an answer here:
I have something like this:
class Bar
{
public:
pair<string,string> one;
std::vector<string> cars;
Bar(string one, string two, string car);
};
class Car
{
public:
string rz;
Bar* owner;
Car(string car, Bar* p);
};
class Foo
{
public:
Foo ( void );
~Foo ( void );
int Count ( const string & one, const string & two) const;
int comparator (const Bar & first, const Bar & second) const;
std::vector<Bar> bars;
};
int Foo::comparator(const Bar & first, const Bar & second) const{
return first.name < second.name;
}
int Foo::Count ( const string & one, const string & two ) const{
int result=0;
Bar mybar = Bar( one, two, "" );
std::vector<Bar>::iterator ToFind = lower_bound(bars.begin(), bars.end(), mybar, comparator);
if (ToFind != bars.end() && ToFind->one == mybar.one ){
result = ...
}
return result;
}
The method Foo::Count
should use std::lower_bound()
to find element in vector<Bar>
according to pair of two strings.
Now the part which doesn't work. To lower_bound()
I'm providing method comparator()
. I thought it was okay, but g++ says:
c.cpp: In member function ‘int Foo::Count(const string&, const string&) const’:
c.cpp:42:94: error: invalid use of non-static member function
std::vector<Bar>::iterator ToFind = lower_bound(bars.begin(), bars.end(), mybar, comparator);
And the method Count()
must stay const
...
I'm quite new to C++ because I'm forced to learn it.
Any ideas?
You must make Foo::comparator
static or wrap it in a std::mem_fun
class object. This is because lower_bounds expects the comparor to be a class of object that has a call operator, like a function pointer or a functor object. Also, if you are using C++11 or later, you can also do as dwcanillas suggests and use a lambda function. C++11 also has std::bind
too.
Examples:
// Binding:
std::lower_bounds(first, last, value, std::bind(&Foo::comparitor, this, _1, _2));
// Lambda:
std::lower_bounds(first, last, value, [](const Bar & first, const Bar & second) { return ...; });
The simplest fix is to make the comparator function be static:
static int comparator (const Bar & first, const Bar & second);
^^^^^^
When invoking it in Count
, its name will be Foo::comparator
.
The way you have it now, it does not make sense to be a non-static member function because it does not use any member variables of Foo
.
Another option is to make it a non-member function, especially if it makes sense that this comparator might be used by other code besides just Foo
.
You shall pass a this
pointer to tell the function which object to work on because it relies on that as opposed to a static
member function.
来源:https://stackoverflow.com/questions/29286863/invalid-use-of-non-static-member-function