Display exact matches only with GREP

Question

How can I display all jobs that ended OK only?

When I try the command below, it shows both OK and NOTOK since both have "OK"

ctmpsm -listall application | grep OK

Answer 1

You need a more specific expression. Try grep " OK$" or grep "[0-9]* OK". You want to choose a pattern that matches what you want, but won't match what you don't want. That pattern will depend upon what your whole file contents might look like.

You can also do: grep -w "OK" which will only match a whole word "OK", such as "1 OK" but won't match "1OK" or "OKFINE".

$ cat test.txt | grep -w "OK"
1 OK
2 OK
4 OK

Answer 2

This may work for you

grep -E '(^|\s)OK($|\s)'

Answer 3

Try this:

Alex Misuno@hp4530s ~
$ cat test.txt
1 OK
2 OK
3 NOTOK
4 OK
5 NOTOK
Alex Misuno@hp4530s ~
$ cat test.txt | grep ".* OK$"
1 OK
2 OK
4 OK

Answer 4

This worked for me:

grep  "\bsearch_word\b"  text_file > output.txt  ## \b indicates boundaries. This is much faster.

or,

grep -w "search_word" text_file > output.txt

Answer 5

try this: grep -P '^(tomcat!?)' tst1.txt

It will search for specific word in txt file. Here we are trying to search word 'tomcat'

Answer 6

Try the below command, because it works perfectly:

grep -ow "yourstring"

crosscheck:-

Remove the instance of word from file, then re-execute this command and it should display empty result.