invalid use of non-static member function [duplicate]

问题

I have something like this:

class Bar
      {
      public:
        pair<string,string> one;
        std::vector<string> cars;
        Bar(string one, string two, string car);
      };

class Car
      {
      public:
        string rz;
        Bar* owner;
        Car(string car, Bar* p);
      };

class Foo
       {
         public:
          Foo  ( void );
          ~Foo  ( void );
          int Count ( const string & one, const string &  two) const;
          int comparator (const Bar & first, const Bar & second) const;            
            std::vector<Bar> bars;
       };

int Foo::comparator(const Bar & first, const Bar & second) const{
  return first.name < second.name;
}

int Foo::Count  ( const string & one, const string & two ) const{
  int result=0;
  Bar mybar = Bar( one, two, "" );
  std::vector<Bar>::iterator ToFind = lower_bound(bars.begin(), bars.end(), mybar, comparator);
  if (ToFind != bars.end() && ToFind->one == mybar.one ){
    result = ...
  }
  return result;
}

The method Foo::Count should use std::lower_bound() to find element in vector<Bar> according to pair of two strings. Now the part which doesn't work. To lower_bound() I'm providing method comparator(). I thought it was okay, but g++ says:

c.cpp: In member function ‘int Foo::Count(const string&, const string&) const’:
c.cpp:42:94: error: invalid use of non-static member function
std::vector<Bar>::iterator ToFind = lower_bound(bars.begin(), bars.end(), mybar, comparator);

And the method Count() must stay const...

I'm quite new to C++ because I'm forced to learn it.

Any ideas?

回答1:

You must make Foo::comparator static or wrap it in a std::mem_fun class object. This is because lower_bounds expects the comparor to be a class of object that has a call operator, like a function pointer or a functor object. Also, if you are using C++11 or later, you can also do as dwcanillas suggests and use a lambda function. C++11 also has std::bind too.

Examples:

// Binding:
std::lower_bounds(first, last, value, std::bind(&Foo::comparitor, this, _1, _2));
// Lambda:
std::lower_bounds(first, last, value, [](const Bar & first, const Bar & second) { return ...; });

回答2:

The simplest fix is to make the comparator function be static:

static int comparator (const Bar & first, const Bar & second);
^^^^^^

When invoking it in Count, its name will be Foo::comparator.

The way you have it now, it does not make sense to be a non-static member function because it does not use any member variables of Foo.

Another option is to make it a non-member function, especially if it makes sense that this comparator might be used by other code besides just Foo.

回答3:

You shall pass a this pointer to tell the function which object to work on because it relies on that as opposed to a static member function.

来源：https://stackoverflow.com/questions/29286863/invalid-use-of-non-static-member-function

标签

c++

function

const

member

non-static