How can I skip first several lines of the Excel sheet?

Question

Using openpyxl I tried to read from the fifth line for some files. The files' first four lines are the header. Then the main content has a different format from the header. And I tried the method:

import openpyxl
file_name="xxx.xlsx"
wb = openpyxl.load_workbook(filename=file_name, use_iterators = True)
first_sheet = workbook.get_sheet_names()[0]
ws = workbook.get_sheet_by_name(first_sheet)

for index, row in enumerate(ws.iter_rows()):
    if start < index < stop:
        for c in row:
           print c.value

It will always have the error:

IndexError: list index out of range

If I delete the first four lines, the data can be read into Python easily. But I have hundreds of such files, each file has a header for four lines. It will take way much time to delete all the headers from the files.

How to skip first several lines when reading using openpyxl correctly?

Answer 1

You can pass a range into ws.iter_rows('A4:Z256') but you're probably better off using ws.get_squared_range(1, 5,)

Answer 2

You can skip the first N rows by passing the optional min_row argument. Note that this uses a 1-base index, so min_row=2 starts on the second row and min_row=5 skips the first four rows. You would be using something like this:

for index, row in enumerate(ws.iter_rows(min_row=5)):

Full iter_rows documentation.