Dictionary that covert a string to OTAN phonetic alphabet

问题

The user enter a word that which is converted to OTAN phonetic alphabet.

I have to use a dictionary and I put this code:

def otan():


    dictionary = {'A':'Alpha', 'B':'Bravo','C':'Charlie', 'D':'Delta', 'E':'Echo', 'F':'Foxtrot', 'G':'Golf', 'I':'India', 'J':'Juliet', 'K':'Kilo', 'L':'Lima', 'M':'Mike', 'N':'November', 'O':'Oscar', 'P':'Papa', 'Q':'Quebec', 'R':'Romeo', 'S':'Sierra', 'T':'Tango', 'U':'Uniform', 'V':'Victor', 'W':'Whiskey', 'X':'Xray', 'Y':'Yankee', 'Z':'Zulu'}
    input('Enter a word:')

otan()

I enter a word for exemple GH

But appears this : NameError: name 'GH' is not defined

I dont understand the error because the dictionary includes the letter G and H

回答1:

You need to access each keys separately and use raw_input, GH would be two keys not one

dictionary = {'A':'Alpha', 'B':'Bravo','C':'Charlie', 'D':'Delta', 'E':'Echo', 'F':'Foxtrot', 'G':'Golf',"H":"Hotel", 'I':'India', 'J':'Juliet', 'K':'Kilo', 'L':'Lima', 'M':'Mike', 'N':'November', 'O':'Oscar', 'P':'Papa', 'Q':'Quebec', 'R':'Romeo', 'S':'Sierra', 'T':'Tango', 'U':'Uniform', 'V':'Victor', 'W':'Whiskey', 'X':'Xray', 'Y':'Yankee', 'Z':'Zulu'}

inp = raw_input('Enter a word:')
print(" ".join(map(dictionary.get,inp)))
Enter a word:GH
Golf Hotel

回答2:

You mean this?

def otan(word):
  dictionary = {'A':'Alpha', 'B':'Bravo','C':'Charlie', 'D':'Delta', 'E':'Echo', 'F':'Foxtrot', 'G':'Golf', 'I':'India', 'J':'Juliet', 'K':'Kilo', 'L':'Lima', 'M':'Mike', 'N':'November', 'O':'Oscar', 'P':'Papa', 'Q':'Quebec', 'R':'Romeo', 'S':'Sierra', 'T':'Tango', 'U':'Uniform', 'V':'Victor', 'W':'Whiskey', 'X':'Xray', 'Y':'Yankee', 'Z':'Zulu'}
  phon = [dictionary[w] for w in word]
  return ' '.join(phon)

word = raw_input('Enter word: ')
print otan(word)

BTW. If you want to enter word GH in your dictionary there is no H

回答3:

You are using Python2, so you need to use raw_input('Enter word:').

Next, when you get the word from the user, you need to fetch for each letter, the corresponding word from your dictionary:

d = {'A':'Alpha', 'B':'Bravo','C':'Charlie', 'D':'Delta', 'E':'Echo', 'F':'Foxtrot', 'G':'Golf', 'I':'India', 'J':'Juliet', 'K':'Kilo', 'L':'Lima', 'M':'Mike', 'N':'November', 'O':'Oscar', 'P':'Papa', 'Q':'Quebec', 'R':'Romeo', 'S':'Sierra', 'T':'Tango', 'U':'Uniform', 'V':'Victor', 'W':'Whiskey', 'X':'X-ray', 'Y':'Yankee', 'Z':'Zulu'}

word = raw_input('Enter word:')
for letter in word:
   print(d.get(letter.upper()), end='')

A simpler way to write the same loop is:

word = raw_input('Enter word:')
print(' '.join(d.get(letter.upper(), letter) for letter in word))

Here is a sample run:

>>> word = raw_input('Enter word:')
Enter word:PYTHON
>>> print(' '.join(d.get(letter.upper(), letter) for letter in word))
Papa Yankee Tango H Oscar November

You are missing H in your original dictionary, which is why it is showing as is.

来源：https://stackoverflow.com/questions/26324038/dictionary-that-covert-a-string-to-otan-phonetic-alphabet

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python

dictionary