问题
Is there a simple and quick way to multiply a column of a matrix with element of a vector. We can do this explicitly,
program test
integer :: x(3,3), y(3), z(3,3)
x = reshape([(i,i=1,9)],[3,3])
y = [1,2,3]
do i=1,3
z(:,i) = x(:,i) * y(i)
print *, z(:,i)
enddo
end program test
Is there a way to perform the do loop in one line. For example in Numpy python we can do this to do the job in one shot
z = np.einsum('ij,i->ij',x,y)
#or
z = x*y[:,None]
回答1:
Try
z = x * spread(y,1,3)
and if that doesn't work (no Fortran on this computer so I haven't checked) fiddle around with spread
until it does. In practice you'll probably want to replace the 3
by size(x,1)
or suchlike.
I expect that this will cause the compiler to create temporary arrays. And I expect it will be easy to find situations where it underperforms the explicit looping scheme in the question. 'neat' one-liners often have a cost in both time and space. And often tried-and-trusted Fortran approach of explicit looping is the one to go with.
回答2:
Why replace clear easy to read code with garbage?
program test
implicit none
integer i,j
integer :: x(3,3), y(3), z(3,3)
x = reshape([(i,i=1,9)],[3,3])
y = [1,2,3]
z = reshape ([((x(j,i)*y(i) ,j=1,3),i=1,3)], [3,3])
print *, z(1,:)
print *, z(2,:)
print *, z(3,:)
end program test
来源:https://stackoverflow.com/questions/59269264/fortran-element-wise-multiplication-of-a-matrix-and-a-vector