问题
I am trying to read a data file written by a Fortran program, in which every once in a while there is a very small float like 0.3299880-104
. The error message is:
>np.loadtxt(filename, usecols = (1,))
File "/home/anaconda2/lib/python2.7/site-packages/numpy/lib/npyio.py", line 928, in loadtxt
items = [conv(val) for (conv, val) in zip(converters, vals)]
File "/home/anaconda2/lib/python2.7/site-packages/numpy/lib/npyio.py", line 659, in floatconv
return float(x)
ValueError: invalid literal for float(): 0.3299880-104
Can I do something to make Numpy able to read this data file anyway?
回答1:
As @agentp mentioned in the comments, one approach would be to use the converters=
argument to np.genfromtxt to insert the e
characters before casting to float:
import numpy as np
# some example strings
strings = "0.3299880-104 0.3299880+104 0.3299880"
# create a "dummy file" (see http://stackoverflow.com/a/11970414/1461210)
try:
from StringIO import StringIO # Python2
f = StringIO(strings)
except ImportError:
from io import BytesIO # Python3
f = BytesIO(strings.encode())
c = lambda s: float(s.decode().replace('+', 'e').replace('-', 'e-'))
data = np.genfromtxt(f, converters=dict(zip(range(3), [c]*3)))
print(repr(data))
# array([ 3.29988000e-105, 3.29988000e+103, 3.29988000e-001])
来源:https://stackoverflow.com/questions/34545060/reading-a-file-with-fortran-formatted-small-floats-using-numpy