问题
I need to write to a file (truncating) and the path it is on itself might not exist). For example, I want to write to /tmp/a/b/c/config
, but /tmp/a
itself might not exist. Then, open('/tmp/a/b/c/config', 'w')
would not work, obviously, since it doesn't make the necessary directories. However, I can work with the following code:
import os
config_value = 'Foo=Bar' # Temporary placeholder
config_dir = '/tmp/a/b/c' # Temporary placeholder
config_file_path = os.path.join(config_dir, 'config')
if not os.path.exists(config_dir):
os.makedirs(config_dir)
with open(config_file_path, 'w') as f:
f.write(config_value)
Is there a more Pythonic way to do this? Both Python 2.x and Python 3.x would be nice to know (even though I use 2.x in my code, due to dependency reasons).
回答1:
If you're repeating this pattern in multiple places, you could create your own Context Manager that extends open()
and overloads __enter__()
:
import os
class OpenCreateDirs(open):
def __enter__(self, filename, *args, **kwargs):
file_dir = os.path.dirname(filename)
if not os.path.exists(file_dir):
os.makedirs(file_dir)
super(OpenCreateDirs, self).__enter__(filename, *args, **kwargs)
Then your code becomes:
import os
config_value = 'Foo=Bar' # Temporary placeholder
config_file_path = os.path.join('/tmp/a/b/c', 'config')
with OpenCreateDirs(config_file_path, 'w') as f:
f.write(config_value)
The first method to be called when you run with open(...) as f:
is open.__enter__()
. So by creating directories before calling super(...).__enter__()
, you create the directories before attempting to open the file.
来源:https://stackoverflow.com/questions/37711216/recursively-create-directories-prior-to-opening-file-for-writing