问题
The task I wish to accomplish is the following: Consider a 1-D array a
and an array of indices parts
of length N
. Example:
a = np.arange(9)
parts = np.array([4, 6, 9])
# a = array([0, 1, 2, 3, 4, 5, 6, 7, 8])
I want to cast a
into a 2-D array of shape (N, <length of longest partition in parts>)
, inserting values of a
upto each index in indx
in each row of the 2-D array, filling the remaining part of the row with zeroes, like so:
array([[0, 1, 2, 3],
[4, 5, 0, 0],
[6, 7, 8, 0])
I do not wish to use loops. Can't wrap my head around this, any help is appreciated.
回答1:
Here's one with boolean-indexing
-
def jagged_to_regular(a, parts):
lens = np.ediff1d(parts,to_begin=parts[0])
mask = lens[:,None]>np.arange(lens.max())
out = np.zeros(mask.shape, dtype=a.dtype)
out[mask] = a
return out
Sample run -
In [46]: a = np.arange(9)
...: parts = np.array([4, 6, 9])
In [47]: jagged_to_regular(a, parts)
Out[47]:
array([[0, 1, 2, 3],
[4, 5, 0, 0],
[6, 7, 8, 0]])
来源:https://stackoverflow.com/questions/62838234/reshape-jagged-array-and-fill-with-zeros