问题
My guess was to use the following syntax:
MyModel::all()->delete();
But that did not work. I'm sure it's super simple, but I've searched for documentation on the subject and can't find it!
回答1:
The reason MyModel::all()->delete() doesn't work is because all() actually fires off the query and returns a collection of Eloquent objects.
You can make use of the truncate method, this works for Laravel 4 and 5:
MyModel::truncate();
That drops all rows from the table without logging individual row deletions.
回答2:
Laravel 5.2+ solution.
Model::getQuery()->delete();
Just grab underlying builder with table name and do whatever. Couldn't be any tidier than that.
Laravel 5.6 solution
\App\Model::query()->delete();
回答3:
You can use Model::truncate() if you disable foreign_key_checks (I assume you use MySQL).
DB::statement("SET foreign_key_checks=0");
Model::truncate();
DB::statement("SET foreign_key_checks=1");
回答4:
I've seen both methods been used in seed files.
// Uncomment the below to wipe the table clean before populating
DB::table('table_name')->truncate();
//or
DB::table('table_name')->delete();
Even though you can not use the first one if you want to set foreign keys.
Cannot truncate a table referenced in a foreign key constraint
So it might be a good idea to use the second one.
回答5:
There is an indirect way:
myModel:where('anyColumnName', 'like', '%%')->delete();
Example:
User:where('id', 'like' '%%')->delete();
Laravel query builder information: https://laravel.com/docs/5.4/queries
回答6:
I wanted to add another option for those getting to this thread via Google. I needed to accomplish this, but wanted to retain my auto-increment value which truncate() resets. I also didn't want to use DB:: anything because I wanted to operate directly off of the model object. So, I went with this:
Model::whereNotNull('id')->delete();
Obviously the column will have to actually exists, but in a standard, out-of-the-box Eloquent model, the id column exists and is never null. I don't know if this is the best choice, but it works for my purposes.
回答7:
I wasn't able to use Model::truncate() as it would error:
SQLSTATE[42000]: Syntax error or access violation: 1701 Cannot truncate a table referenced in a foreign key constraint
And unfortunately Model::delete() doesn't work (at least in Laravel 5.0):
Non-static method Illuminate\Database\Eloquent\Model::delete() should not be called statically, assuming $this from incompatible context
But this does work:
(new Model)->newQuery()->delete()
That will soft-delete all rows, if you have soft-delete set up. To fully delete all rows including soft-deleted ones you can change to this:
(new Model)->newQueryWithoutScopes()->forceDelete()
回答8:
The best way for accomplishing this operation in Laravel 3 seems to be the use of the Fluent interface to truncate the table as shown below
DB::query("TRUNCATE TABLE mytable");
回答9:
You can try this one-liner which preserves soft-deletes also:
Model::whereRaw('1=1')->delete();
回答10:
In a similar vein to Travis vignon's answer, I required data from the eloquent model, and if conditions were correct, I needed to either delete or update the model. I wound up getting the minimum and maximum I'd field returned by my query (in case another field was added to the table that would meet my selection criteria) along with the original selection criteria to update the fields via one raw SQL query (as opposed to one eloquent query per object in the collection).
I know the use of raw SQL violates laravels beautiful code philosophy, but itd be hard to stomach possibly hundreds of queries in place of one.
回答11:
Can do a foreachloop too..
$collection = Model::get();
foreach($collection as $c) {
$c->delete();
}
回答12:
Solution who works with Lumen 5.5 with foreign keys constraints :
$categories = MusicCategory::all();
foreach($categories as $category)
{
$category->delete();
}
return response()->json(['error' => false]);
回答13:
simple solution:
Mymodel::query()->delete();
来源：https://stackoverflow.com/questions/15484404/how-to-delete-all-the-rows-in-a-table-using-eloquent