How do I generate random numbers in Dart?

问题

How do I generate random numbers using Dart?

回答1:

Use Random class from dart:math:

import 'dart:math';

main() {
  var rng = new Random();
  for (var i = 0; i < 10; i++) {
    print(rng.nextInt(100));
  }
}

This code was tested with the Dart VM and dart2js, as of the time of this writing.

回答2:

If you need cryptographically-secure random numbers (e.g. for encryption), and you're in a browser, you can use the DOM cryptography API:

int random() {
  final ary = new Int32Array(1);
  window.crypto.getRandomValues(ary);
  return ary[0];
}

This works in Dartium, Chrome, and Firefox, but likely not in other browsers as this is an experimental API.

回答3:

Here's a snippet for generating a list of random numbers

import 'dart:math';

main() {
  var rng = new Random();
  var l = new List.generate(12, (_) => rng.nextInt(100));
}

This will generate a list of 12 integers from 0 to 99 (inclusive).

回答4:

You can achieve it via Random class object random.nextInt(max), which is in dart:math library. The nextInt() method requires a max limit. The random number starts from 0 and the max limit itself is exclusive.

import 'dart:math';
Random random = new Random();
int randomNumber = random.nextInt(100); // from 0 upto 99 included

If you want to add the min limit, add the min limit to the result

int randomNumber = random.nextInt(90) + 10; // from 10 upto 99 included

回答5:

A secure random API was just added to dart:math

new Random.secure()

dart:math Random added a secure constructor returning a cryptographically secure random generator which reads from the entropy source provided by the embedder for every generated random value.

which delegates to window.crypto.getRandomValues() in the browser and to the OS (like urandom on the server)

回答6:

Not able to comment because I just created this account, but I wanted to make sure to point out that @eggrobot78's solution works, but it is exclusive in dart so it doesn't include the last number. If you change the last line to "r = min + rnd.nextInt(max - min + 1);", then it should include the last number as well.

Explanation:

max = 5;
min = 3;
Random rnd = new Random();
r = min + rnd.nextInt(max - min);
//max - min is 2
//nextInt is exclusive so nextInt will return 0 through 1
//3 is added so the line will give a number between 3 and 4
//if you add the "+ 1" then it will return a number between 3 and 5

回答7:

An alternative solution could be using the following code DRandom. This class should be used with a seed. It provides a familiar interface to what you would expect in .NET, it was ported from mono's Random.cs. This code may not be cryptography safe and has not been statistically tested.

回答8:

Just wrote this little class for generating Normal Random numbers... it was a decent starting point for the checking I need to do. (These sets will distribute on a "bell" shaped curve.) The seed will be set randomly, but if you want to be able to re-generate a set you can just pass some specific seed and the same set will generate.

Have fun...

class RandomNormal {
  num     _min, _max,  _sum;
  int     _nEle, _seed, _hLim;
  Random  _random;
  List    _rNAr;

  //getter
  List get randomNumberAr => _rNAr;

  num _randomN() {
    int r0 = _random.nextInt(_hLim);
    int r1 = _random.nextInt(_hLim);
    int r2 = _random.nextInt(_hLim);
    int r3 = _random.nextInt(_hLim);

    num rslt = _min + (r0 + r1 + r2 + r3) / 4000.0;  //Add the OS back in...
    _sum += rslt; //#DEBUG ONLY
    return( rslt );
  }

  RandomNormal(this._nEle, this._min, this._max, [this._seed = null]) {
    if (_seed == null ) {
      Random r = new Random();
      _seed    = r.nextInt(1000);
    }
    _hLim   = (_max - _min).ceil() * 1000;
    _random = new Random(_seed);
    _rNAr   = [];
    _sum    = 0;//#DEBUG ONLY

    h2("RandomNormal with k: ${_nEle}, Seed: ${_seed}, Min: ${_min}, Max: ${_max}");//#DEBUG ONLY
    for(int n = 0; n < _nEle; n++ ){
      num randomN = _randomN();
      //p("randomN  = ${randomN}");
      LIST_add( _rNAr, randomN );
    }

    h3("Mean = ${_sum/_nEle}");//#DEBUG ONLY
  }
}


new RandomNormal(1000, 80, 120);
new RandomNormal(1000, 80, 120);
new RandomNormal(1000, 80, 120);
new RandomNormal(1000, 80, 120);
new RandomNormal(1000, 80, 120);
new RandomNormal(1000, 80, 120);
new RandomNormal(1000, 80, 120);

Then you can just use it like this to check the mean of sets of 1000 nums generated between a low and high limit. The values are stored in the class so they can be accessed after instantiation.

_swarmii

回答9:

use this library http://dart.googlecode.com/svn/branches/bleeding_edge/dart/lib/math/random.dart provided a good random generator which i think will be included in the sdk soon hope it helps

回答10:

For me the easiest way is to do:

import 'dart:math';
Random rnd = new Random();
r = min + rnd.nextInt(max - min);
//where min and max should be specified.

Thanks to @adam-singer explanation in here.

回答11:

its worked for me new Random().nextInt(100); // MAX = number

it will give 0 to 99 random number

Eample::

import 'dart:math';
int MAX = 100;
print(new Random().nextInt(MAX));`

来源：https://stackoverflow.com/questions/11674820/how-do-i-generate-random-numbers-in-dart

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random

dart