I just wondered whether it's possible to match against the same values for multiple times with the pattern matching facilities of functional programming languages (Haskell/F#/Caml).
Just think of the following example:
plus a a = 2 * a
plus a b = a + b
The first variant would be called when the function is invoked with two similar values (which would be stored in a
).
A more useful application would be this (simplifying an AST).
simplify (Add a a) = Mult 2 a
But Haskell rejects these codes and warns me of conflicting definitions for a
- I have to do explicit case/if-checks instead to find out whether the function got identical values. Is there any trick to indicate that a variable I want to match against will occur multiple times?
This is called a nonlinear pattern. There have been several threads on the haskell-cafe mailing list about this, not long ago. Here are two:
http://www.mail-archive.com/haskell-cafe@haskell.org/msg59617.html
http://www.mail-archive.com/haskell-cafe@haskell.org/msg62491.html
Bottom line: it's not impossible to implement, but was decided against for sake of simplicity.
By the way, you do not need if
or case
to work around this; the (slightly) cleaner way is to use a guard:
a `plus` b
| a == b = 2*a
| otherwise = a+b
You can't have two parameters with the same name to indicate that they should be equal, but you can use guards to distinguish cases like this:
plus a b
| a == b = 2 * a
| otherwise = a + b
This is more flexible since it also works for more complicated conditions than simple equality.
I have just looked up the mailing list threads given in Thomas's answer, and the very first reply in one of them makes good sense, and explains why such a "pattern" would not make much sense in general: what if a
is a function? (It is impossible in general to check it two functions are equal.)
Haskell doesn't do unification.
I have implemented a new functional programming language that can handle non-linear patterns in Haskell.
https://github.com/egison/egison
In my language, your plus
function in written as follow.
(define $plus
(match-lambda [integer integer]
{[[$a ,a] (* a 2)]
[[$a $b] (+ a b)]}))
来源:https://stackoverflow.com/questions/1179008/pattern-matching-identical-values