问题
I am trying to pass path param and query params in a URL but I am getting a weird error. below is the code
String url = "http://test.com/Services/rest/{id}/Identifier"
Map<String, String> params = new HashMap<String, String>();
params.put("id", "1234");
UriComponentsBuilder builder = UriComponentsBuilder.fromUriString(url)
.queryParam("name", "myName");
String uriBuilder = builder.build().encode().toUriString();
restTemplate.exchange(uriBuilder , HttpMethod.PUT, requestEntity,
class_p, params);
and my url is becoming http://test.com/Services/rest/%7Bid%7D/Identifier?name=myName
what should I do to make it work. I am expecting http://test.com/Services/rest/{id}/Identifier?name=myName
so that params will add id to the url
please suggest. thanks in Advance
回答1:
I would use buildAndExpand
from UriComponentsBuilder
to pass all types of URI parameters.
For example:
String url = "http://test.com/solarSystem/planets/{planet}/moons/{moon}";
// URI (URL) parameters
Map<String, String> urlParams = new HashMap<String, String>();
urlParams.put("planets", "Mars");
urlParams.put("moons", "Phobos");
// Query parameters
UriComponentsBuilder builder = UriComponentsBuilder.fromUriString(url)
// Add query parameter
.queryParam("firstName", "Mark")
.queryParam("lastName", "Watney");
System.out.println(builder.buildAndExpand(urlParams).toUri());
/**
* Console output:
* http://test.com/solarSystem/planets/Mars/moons/Phobos?firstName=Mark&lastName=Watney
*/
restTemplate.exchange(builder.buildAndExpand(urlParams).toUri() , HttpMethod.PUT,
requestEntity, class_p);
/**
* Log entry:
* org.springframework.web.client.RestTemplate Created PUT request for "http://test.com/solarSystem/planets/Mars/moons/Phobos?firstName=Mark&lastName=Watney"
*/
回答2:
An issue with the answer from Michal Foksa is that it adds the query parameters first, and then expands the path variables. If query parameter contains parenthesis, e.g. {foobar}
, this will cause an exception.
The safe way is to expand the path variables first, and then add the query parameters:
String url = "http://test.com/Services/rest/{id}/Identifier";
Map<String, String> params = new HashMap<String, String>();
params.put("id", "1234");
URI uri = UriComponentsBuilder.fromUriString(url)
.buildAndExpand(params)
.toUri();
uri = UriComponentsBuilder
.fromUri(uri)
.queryParam("name", "myName")
.build()
.toUri();
restTemplate.exchange(uri , HttpMethod.PUT, requestEntity, class_p);
回答3:
One-liner using TestRestTemplate.exchange function with parameters map.
restTemplate.exchange("/someUrl?id={id}", HttpMethod.GET, reqEntity, respType, ["id": id])
The params map initialized like this is a groovy initializer*
来源:https://stackoverflow.com/questions/35998790/resttemplate-how-to-send-url-and-query-parameters-together