Insert and Update syntax error on Database / Datagrid

萝らか妹 提交于 2020-01-24 20:16:06

问题


Here is my button command for save. need help in getting this to work, will be getting this to defend for tomorrow school project. Thanks! Its for Datagridview, access, c#. I use 2010VS and MS Access 2007.

private void save_Click(object sender, EventArgs e)
    {

        if (adminyes.Checked == true || adminno.Checked == true && textBox1.Text != null && textBox2.Text != null && textBox3.Text != null)
        {
            admin = "Yes";

            if (mode == "a")
            {
                x = 0;
                connect.Close();
                connect.ConnectionString = inventorydb;
                connect.Open();
                sqlcommand.CommandText = "SELECT * FROM Users WHERE Username ='" +textBox2.Text+ "' Or User_ID ='" +textBox1.Text+ "' ";
                sqlcommand.Connection = connect;
                OleDbDataReader reader = sqlcommand.ExecuteReader();
                while (reader.Read())
                {
                    x++;
                }

                if (x != 0)
                {
                    MessageBox.Show("", "",MessageBoxButtons.OK);
                }
                else
                {
                    DialogResult res = MessageBox.Show("Are you sure?", "Save User", MessageBoxButtons.YesNo, MessageBoxIcon.Warning);

                    if (DialogResult.Yes == res)
                    {
                        connect.Close();
                        connect.ConnectionString = inventorydb;
                        connect.Open();
                        sqlcommand.CommandText = "INSERT INTO Users (User_ID, Username, Password, Admin) VALUES ('" + textBox1.Text + "','" + textBox2.Text + "', '" + textBox3.Text + "', '" + admin + "') ";
                        sqlcommand.Connection = connect;
                        reader = sqlcommand.ExecuteReader();
                        MessageBox.Show("Record(s) Saved", "Sample");
                    }

                    reset();
                }
            }
            else if (mode == "e")
            {
                DialogResult res = MessageBox.Show("Are you sure?", "Update User", MessageBoxButtons.YesNo, MessageBoxIcon.Warning);

                if (DialogResult.Yes == res)
                {
                    connect.Close();
                    connect.ConnectionString = inventorydb;
                    connect.Open();
                    sqlcommand.CommandText = "UPDATE Users SET User_ID = '" + textBox1.Text + "',  Username = '" + textBox2.Text + "', Password = '" + textBox3.Text + "',Admin = '" + admin + "' WHERE SerialID = '" + idholder + "'  ";
                    sqlcommand.Connection = connect;
                    OleDbDataReader reader = sqlcommand.ExecuteReader();
                    reader.Read();
                    MessageBox.Show("Record(s) Updated", "Sample");

                }

                reset();
            }
        }
        else 
        {
            MessageBox.Show("", "", MessageBoxButtons.OK, MessageBoxIcon.Error);
        }
    }

回答1:


Password is a reserved word in Access. Change it to [Password] in your SQL queries. You should wrap all columns and tables like this.

Although this is just a school project I'll mention a few things:

Your code is vulnerable to SQL injection. Here's how to fix this for your insert method as an example:

sqlcommand.CommandText = "INSERT INTO [Users] ([User_ID], [Username], [Password], [Admin]) VALUES (@user_id, @username, @password, @admin)";
sqlcommand.Connection = connect;
sqlcommand.Parameters.AddWithValue("@user_id", textBox1.Text);
sqlcommand.Parameters.AddWithValue("@username", textBox2.Text);
sqlcommand.Parameters.AddWithValue("@password", textBox3.Text);
sqlcommand.Parameters.AddWithValue("@admin", admin);
reader = sqlcommand.ExecuteReader();

Also passwords shouldn't be stored in plain text. Look into password hashing and salting and how to approach it properly for more information.



来源:https://stackoverflow.com/questions/39688685/insert-and-update-syntax-error-on-database-datagrid

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