Decoding unknown Encodable enum values to a default

问题

I have to deserialize a JSON string like this:

{ "name" : "John Smith", "value" : "someValue" }

in Swift 4, where "value" should be a enum and the whole object is a struct like:

struct MyType {
    name: String?
    value: Value?
}

At some point in the future, there might be new enum values added in the backend so I thought it would be smart to have some fallback.

I thought I could create a enum like

enum Value {
    case someValue
    case someOtherValue
    case unknown(value: String)
}

but I just can't wrap my head around how to deserialize that enum and make it work. Previously I simply used a String enum, but deserializing unknown values throws errors.

Is there a simple way to make that work or should I deserialize the value as a String and create a custom getter in the struct with a switch statement to return one of the cases (probably not even in the struct itself but in my view model)?

回答1:

You can implement init(from decoder: Decoder) and encode(to encoder: Encoder) and handle every case explicitly, i.e.

struct MyType: Codable
{
    var name: String?
    var value: Value?

    enum CodingKeys: String, CodingKey
    {
        case name
        case value
    }

    init(from decoder: Decoder) throws
    {
        let values = try decoder.container(keyedBy: CodingKeys.self)
        name = try values.decode(String.self, forKey: .name)
        let strValue = try values.decode(String.self, forKey: .value)
        //You need to handle every case explicitly
        switch strValue
        {
        case "someValue":
            value = Value.someValue
        case "someOtherValue":
            value = Value.someOtherValue
        default:
            value = Value.unknown(value: strValue)
        }
    }

    func encode(to encoder: Encoder) throws
    {
        var container = encoder.container(keyedBy: CodingKeys.self)
        try container.encode(name, forKey: .name)
        if let val = value
        {
            //You need to handle every case explicitly
            switch val
            {
            case .someValue, .someOtherValue:
                try container.encode(String(describing: val), forKey: .value)
            case .unknown(let strValue):
                try container.encode(strValue, forKey: .value)
            }
        }
    }
}

enum Value
{
    case someValue
    case someOtherValue
    case unknown(value: String)
}

来源：https://stackoverflow.com/questions/47634348/decoding-unknown-encodable-enum-values-to-a-default

标签

json

swift

enums

deserialization

codable