ddply summarise proportional count

问题

I am having some trouble using the ddply function from the plyr package. I am trying to summarise the following data with counts and proportions within each group. Here's my data:

    structure(list(X5employf = structure(c(1L, 3L, 1L, 1L, 1L, 3L, 
1L, 1L, 1L, 3L, 1L, 1L, 1L, 2L, 2L, 3L, 3L, 3L, 1L, 2L, 2L, 2L, 
2L, 2L, 1L, 1L, 1L, 3L, 3L, 3L, 3L, 3L, 3L, 2L, 1L, 1L, 3L, 1L, 
3L, 2L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 
2L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 3L, 3L, 3L, 
3L, 3L, 1L), .Label = c("increase", "decrease", "same"), class = "factor"), 
    X5employff = structure(c(2L, 6L, NA, 2L, 4L, 6L, 5L, 2L, 
    2L, 8L, 2L, 2L, 2L, 7L, 7L, 8L, 11L, 7L, 2L, 8L, 8L, 11L, 
    7L, 6L, 2L, 5L, 2L, 8L, 7L, 7L, 7L, 8L, 6L, 7L, 5L, 5L, 7L, 
    2L, 6L, 7L, 2L, 2L, 2L, 2L, 2L, 5L, 5L, 5L, 2L, 5L, 2L, 2L, 
    2L, 5L, 12L, 2L, 2L, 2L, 2L, 5L, 5L, 5L, 5L, 2L, 5L, 2L, 
    13L, 9L, 9L, 9L, 7L, 8L, 5L), .Label = c("", "1", "1  and 8", 
    "2", "3", "4", "5", "6", "6 and 7", "6 and 7 ", "7", "8", 
    "1 and 8"), class = "factor")), .Names = c("X5employf", "X5employff"
), row.names = c(NA, 73L), class = "data.frame")

And here's my call using ddply:

ddply(kano_final, .(X5employf, X5employff), summarise, n=length(X5employff), prop=(n/sum(n))*100)

This gives me the counts of each instance of X5employff correctly, but but seems as though the proportion is being calculated across each row and not within each level of the factor X5employf as follows:

   X5employf X5employff  n prop
1   increase          1 26  100
2   increase          2  1  100
3   increase          3 15  100
4   increase    1 and 8  1  100
5   increase       <NA>  1  100
6   decrease          4  1  100
7   decrease          5  5  100
8   decrease          6  2  100
9   decrease          7  1  100
10  decrease          8  1  100
11      same          4  4  100
12      same          5  6  100
13      same          6  5  100
14      same    6 and 7  3  100
15      same          7  1  100

When manually calculating the proportions within each group I get this:

   X5employf X5employff  n prop
1   increase          1 26  59.09
2   increase          2  1  2.27
3   increase          3 15  34.09
4   increase    1 and 8  1  2.27
5   increase       <NA>  1  2.27
6   decrease          4  1  10.00
7   decrease          5  5  50.00
8   decrease          6  2  20.00
9   decrease          7  1  10.00
10  decrease          8  1  10.00
11      same          4  4  21.05
12      same          5  6  31.57
13      same          6  5  26.31
14      same    6 and 7  3  15.78
15      same          7  1  5.26

As you can see the sum of proportions in each level of factor X5employf equals 100.

I know this is probably ridiculously simple, but I can't seem to get my head around it despite reading all sorts of similar posts. Can anyone help with this and my understanding of how the summarise function works?!

Many, many thanks

Marty

回答1:

You cannot do it in one ddply call because what gets passed to each summarize call is a subset of your data for a specific combination of your group variables. At this lowest level, you do not have access to that intermediate level sum(n). Instead, do it in two steps:

kano_final <- ddply(kano_final, .(X5employf), transform,
                    sum.n = length(X5employf))

ddply(kano_final, .(X5employf, X5employff), summarise, 
      n = length(X5employff), prop = n / sum.n[1] * 100)

Edit: using a single ddply call and using table as you hinted towards:

ddply(kano_final, .(X5employf), summarise,
      n          = Filter(function(x) x > 0, table(X5employff, useNA = "ifany")),
      prop       = 100* prop.table(n),
      X5employff = names(n))

回答2:

I'd add here an example with dplyr which makes it quite easily in one step, with a short-code and easy-to-read syntax.

d is your data.frame

library(dplyr)
d%.%
  dplyr:::group_by(X5employf, X5employff) %.%
  dplyr:::summarise(n = length(X5employff)) %.%
  dplyr:::mutate(ngr = sum(n)) %.% 
  dplyr:::mutate(prop = n/ngr*100)

will result in

Source: local data frame [15 x 5]
Groups: X5employf

   X5employf X5employff  n ngr      prop
1   increase          1 26  44 59.090909
2   increase          2  1  44  2.272727
3   increase          3 15  44 34.090909
4   increase    1 and 8  1  44  2.272727
5   increase         NA  1  44  2.272727
6   decrease          4  1  10 10.000000
7   decrease          5  5  10 50.000000
8   decrease          6  2  10 20.000000
9   decrease          7  1  10 10.000000
10  decrease          8  1  10 10.000000
11      same          4  4  19 21.052632
12      same          5  6  19 31.578947
13      same          6  5  19 26.315789
14      same    6 and 7  3  19 15.789474
15      same          7  1  19  5.263158

回答3:

What you apparently want to do is to find out the proportions of X5employff for every value of X5employf. However, you don't tell ddply that X5employf and X5employff are different; to ddply, these two variables are just two variables to split up the data. Also, since there is one observation per line, i.e. count = 1 for every line of the data, the length of each (X5employf, X5employff) combination equals the sum of each (X5employf, X5employff) combination.

The simplest "plyr way" to solve your problem that I can think of is the following:

result <- ddply(kano_final, .(X5employf, X5employff), summarise, n=length(X5employff), drop=FALSE)
n <- result$n
n2 <- ddply(kano_final, .(X5employf), summarise, n=length(X5employff))$n
result <- data.frame(result, prop=n/rep(n2, each=13)*100)

You can also use good old xtabs:

a <- xtabs(~X5employf + X5employff, kano_final)
b <- xtabs(~X5employf, kano_final)
a/matrix(b, nrow=3, ncol=ncol(a))

来源：https://stackoverflow.com/questions/18057081/ddply-summarise-proportional-count

标签

plyr