问题
In Python can you select a random date from a year. e.g. if the year was 2010 a date returned could be 15/06/2010
回答1:
It's much simpler to use ordinal dates (according to which today's date is 734158):
from datetime import date
import random
start_date = date.today().replace(day=1, month=1).toordinal()
end_date = date.today().toordinal()
random_day = date.fromordinal(random.randint(start_date, end_date))
This will fail for dates before 1AD.
回答2:
Not directly, but you could add a random number of days to January 1st. I guess the following should work for the Gregorian calendar:
from datetime import date, timedelta
import random
import calendar
# Assuming you want a random day of the current year
firstJan = date.today().replace(day=1, month=1)
randomDay = firstJan + timedelta(days = random.randint(0, 365 if calendar.isleap(firstJan.year) else 364))
回答3:
import datetime, time
import random
def year_start(year):
return time.mktime(datetime.date(year, 1, 1).timetuple())
def rand_day(year):
stamp = random.randrange(year_start(year), year_start(year + 1))
return datetime.date.fromtimestamp(stamp)
Edit: Ordinal dates as used in Michael Dunns answer are way better to use then timestamps! One might want to combine the use of ordinals with this though.
回答4:
import calendar
import datetime
import random
def generate_random_date(future=True, years=1):
today = datetime.date.today()
#Set the default dates
day = today.day
year = today.year
month = today.month
if future:
year = random.randint(year, year + years)
month = random.randint(month, 12)
date_range = calendar.monthrange(year, month)[1] #dates possible this month
day = random.randint(day + 1, date_range) #1 day in the future
else:
year = random.randint(year, year - years)
month = random.randint(1, month)
day = random.randint(1, day - 1)
return datetime.date(year, month, day)
来源:https://stackoverflow.com/questions/4759223/python-select-random-date-in-current-year