How do I launch a java process that has the standard bash shell environment?

问题

I've tried looking into process builder, but I'm not sure how to source the bash environment into the process.

For example I'm using the following to launch my process:

Process p = new ProcessBuilder(args).start();
InputStream is = p.getInputStream();
InputStreamReader isr = new InputStreamReader(is);
BufferedReader br = new BufferedReader(isr);

And I'd like my standard shell environment (from /etc/profile, .bashrc, etc.) sourced to the process.

Sorry if I'm not using the right terms - still learning java.

Thanks in advance for any help!

回答1:

You need to set up a shell invocation with ProcessBuilder. Execute a command like:

/bin/bash -l -c "The entire command line that you want to execute"

回答2:

Go and get the latest Beanshell .jar file and put it into your Javasoft/jre/lib/ext directory.

Then , you can run Java shell scripts like this:

java bsh.Interpreter myscript.bsh [args]

Or, from within a Java program like so:

Object result = new bsh.Interpreter().source("myscript.bsh");

NOTE: in the second example, the args need to be set separately in the namespace.

回答3:

You can try,

bash -i -c "your command"

Here i stands for interactive screen, which will start by executing the commands present in the ~/.bashrc file

来源：https://stackoverflow.com/questions/7354592/how-do-i-launch-a-java-process-that-has-the-standard-bash-shell-environment