问题
This is my scraping code:
import requests
from bs4 import BeautifulSoup as soup
def get_emails(_links:list):
for i in range(len(_links)):
new_d = soup(requests.get(_links[i]).text, 'html.parser').find_all('a', {'class':'my_modal_open'})
if new_d:
yield new_d[-1]['title']
start=20
while True:
d = soup(requests.get('http://www.schulliste.eu/type/gymnasien/?bundesland=&start=20').text, 'html.parser')
results = [i['href'] for i in d.find_all('a')][52:-9]
results = [link for link in results if link.startswith('http://')]
print(list(get_emails(results)))
next_page=soup.find('div', {'class': 'paging'}, 'weiter')
if next_page:
d=next_page.get('href')
start+=20
else:
break
And thats the error I get: AttributeError: 'str' object has no attribute 'find_all'
When you press the button "weiter" (next page) the urlending changes from "...start=20" to "start=40". It is in 20s steps because there are 20 results per site. Does anyone know the reason for the error?
回答1:
You put the 'soup' in a variable called 'd'.
So replace the following line:
next_page=soup.find('div', {'class': 'paging'}, 'weiter')
With this:
next_page = d.find('div', {'class': 'paging'}, 'weiter')
来源：https://stackoverflow.com/questions/52719131/python-scraping-go-to-next-page-using-beautifulsoup