Automatically determine position of plot legend

半城伤御伤魂 提交于 2020-01-04 02:38:34

问题


You can position the key legend manually in most plotting programs. For example, in gnuplot it's done using set key top right. In ggplot2, it's done like this.

Is there a plotting library, script, or simple algorithm that automatically positions the legend such that it overlaps the data in the plot minimally?

What I mean is: Suppose I plot the line y=x. A good place for the legend in that case would be top left or bottom right.


回答1:


Try this,

require(Hmisc)
?largest.empty

there are other discussions and functions proposed in R-help archives




回答2:


require(plotrix)

?emptyspace     # Find the largest empty space on a plot

This is the example from the help page:

x<-rnorm(100)
 y<-rnorm(100)
 plot(x,y,main="Find the empty space",xlab="X",ylab="Y")
 es<-plotrix::emptyspace(x,y)
 # use a transparent background so that any overplotted points are shown
 plotrix::boxed.labels(es,labels="Here is the\nempty space",bg="transparent")



回答3:


A quick trick to get one of "topleft", "topright", "bottomleft" and "bottomright":

auto.legend.pos <- function(x,y,xlim=range(x),ylim=range(y)) {
  countIt <- function(a,zero.only=TRUE) {
    tl <- sum(x <= xlim[1]*(1-a)+xlim[2]*a & y >= ylim[1]*a+ylim[2]*(1-a))
    tr <- sum(x >= xlim[1]*a+xlim[2]*(1-a) & y >= ylim[1]*a+ylim[2]*(1-a))
    bl <- sum(x <= xlim[1]*(1-a)+xlim[2]*a & y <= ylim[1]*(1-a)+ylim[2]*a)
    br <- sum(x >= xlim[1]*a+xlim[2]*(1-a) & y <= ylim[1]*(1-a)+ylim[2]*a)
    c(topleft=tl,topright=tr,bottomleft=bl,bottomright=br)
  }
  for (k in seq(0.5,0.1,by=-0.05)) {
    a <- countIt(k)
    if (sum(a==0)>0) break
  }
  names(a)[which(a==0)][1]
}

Test:

plot(Sepal.Length~Petal.Length, data=iris)
auto.legend.pos(iris$Petal.Length, iris$Sepal.Length)
# [1] "topleft"


来源:https://stackoverflow.com/questions/7198178/automatically-determine-position-of-plot-legend

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