问题
Flask offers the convenient jsonify()
function, which returns a JSON object from Python variables:
from flask import Flask, jsonify
app = Flask(__name__)
@app.route("/")
def json_hello():
return jsonify({x:x*x for x in range(5)}), 200
if __name__ == "__main__":
app.run(debug=True)
Which returns:
{
"0": 0,
"1": 1,
"2": 4,
"3": 9,
"4": 16
}
(PS - note the conversion from int to string to comply with JSON).
This indented format is wasteful for long outputs, and I prefer the minified version:
{"1": 1, "0": 0, "3": 9, "2": 4, "4": 16}
How can I get the JSON in minified version from Flask's jsonify()
?
回答1:
Simply set the configuration key JSONIFY_PRETTYPRINT_REGULAR to False
- Flask pretty-prints JSON unless it is requested by an AJAX request (by default).
回答2:
In addition to the other answer of JSONIFY_PRETTYPRINT_REGULAR
, you can also get rid of the spaces between list elements by extending flask's jsonencoder, like so:
from flask import Flask
from flask.json import JSONEncoder
class MiniJSONEncoder(JSONEncoder):
"""Minify JSON output."""
item_separator = ','
key_separator = ':'
app = Flask(__name__)
app.json_encoder = MiniJSONEncoder
app.config['JSONIFY_PRETTYPRINT_REGULAR'] = False
The default values for item_separator
and key_separator
have a trailing space each, so by overriding them like this, you remove those spaces from the output.
(strictly speaking I suppose you could just set those values on the default JSONEncoder
but I needed this approach since I had to overload JSONEncoder.default()
for other reasons anyway)
来源:https://stackoverflow.com/questions/25773493/minified-json-in-flasks-jsonify