问题
I have two separate handfuls of REST services in one application. Let's say a main "people" service and a secondary "management" service. What I want is to expose them in separate paths on the server. I am using JAX-RS, RESTEasy and Spring.
Example:
@Path("/people")
public interface PeopleService {
// Stuff
}
@Path("/management")
public interface ManagementService {
// Stuff
}
In web.xml
I currently have the following set-up:
<listener>
<listener-class>org.jboss.resteasy.plugins.server.servlet.ResteasyBootstrap</listener-class>
</listener>
<listener>
<listener-class>org.jboss.resteasy.plugins.spring.SpringContextLoaderListener</listener-class>
</listener>
<context-param>
<param-name>resteasy.servlet.mapping.prefix</param-name>
<param-value>/public</param-value>
</context-param>
<servlet>
<servlet-name>Resteasy</servlet-name>
<servlet-class>
org.jboss.resteasy.plugins.server.servlet.HttpServletDispatcher
</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>Resteasy</servlet-name>
<url-pattern>/public/*</url-pattern>
</servlet-mapping>
The PeopleService
and ManagementService
implementations are just Spring beans.
Above web.xml
configuration will expose them both on /public
(so having /public/people
and /public/management
respectively).
What I want to accomplish is to expose the PeopleService
on /public
, so that the full path would become /public/people
and expose the ManagementService
on /internal
, so that its full path would become /internal/management
.
Unfortunately, I cannot change the value of the @Path
annotation.
How should I do that?
回答1:
actually you can. After few hours of debugging I came up with this:
1) Declare multiple resteasy servlets in your web.xml
(two in my case)
<servlet>
<servlet-name>resteasy-servlet</servlet-name>
<servlet-class>org.jboss.resteasy.plugins.server.servlet.HttpServletDispatcher</servlet-class>
<init-param>
<param-name>resteasy.servlet.mapping.prefix</param-name>
<param-value>/openrest</param-value>
</init-param>
<init-param>
<param-name>resteasy.resources</param-name>
<param-value>com.mycompany.rest.PublicService</param-value>
</init-param>
</servlet>
<servlet>
<servlet-name>private-resteasy-servlet</servlet-name>
<servlet-class>org.jboss.resteasy.plugins.server.servlet.HttpServletDispatcher</servlet-class>
<init-param>
<param-name>resteasy.servlet.mapping.prefix</param-name>
<param-value>/protectedrest</param-value>
</init-param>
<init-param>
<param-name>resteasy.resources</param-name>
<param-value>com.mycompany.rest.PrivateService</param-value>
</init-param>
</servlet>
<servlet-mapping>
<servlet-name>private-resteasy-servlet</servlet-name>
<url-pattern>/protectedrest/*</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>resteasy-servlet</servlet-name>
<url-pattern>/openrest/*</url-pattern>
</servlet-mapping>
Please pay attention to the fact that we initialize personal resteasy.servlet.mapping.prefix
and resteasy.resources
for each our servlet.
Please don't forget to NOT include any botstrap classes as filters or servlets! And disable autoscan as well.
2) Create a filter that cleans up application from the RESTeasy's global information that it saves in context:
public class ResteasyCleanupFilter implements Filter {
@Override
public void init(FilterConfig filterConfig) throws ServletException {
// TODO Auto-generated method stub
}
@Override
public void doFilter(ServletRequest request, ServletResponse response, FilterChain chain) throws IOException,
ServletException {
request.getServletContext().setAttribute(ResteasyProviderFactory.class.getName(), null);
request.getServletContext().setAttribute(Dispatcher.class.getName(), null);
chain.doFilter(request, response);
}
@Override
public void destroy() {
// TODO Auto-generated method stub
}
}
Register it for any request to your services (here I used it for all requests for simplisity):
<filter>
<filter-name>CleanupFilter</filter-name>
<filter-class>com.mycompany.ResteasyCleanupFilter</filter-class>
</filter>
<filter-mapping>
<filter-name>CleanupFilter</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
Thats it!Now you have two different REST services which lays under different prefixes : /openrest
which meant to service all public requests and /protectedrest
that takes care about all the private stuff in the app.
So why does it work (or why it does not work otherwise)?
When you call openrest
instance for the first time it tries to initalize itself and when done saves the state in the global servletContext
like this :
servletContext.setAttribute(ResteasyProviderFactory.class.getName(), deployment.getProviderFactory());
servletContext.setAttribute(Dispatcher.class.getName(), deployment.getDispatcher());
And if you will let it be your call to your second /protectedrest
will get the SAME configuration! That is why you need to clean up this information some where. That is why we used our CleanupFilter
which empty the context so brand new rest servlet could initialize itself with all the init parameters we declared.
This is a hack, but it does the trick.
This solution was tested for RESTEasy 2.3.6
EDITED
Works with 3.0.9.final as well!
回答2:
AFAIK, you cannot have multiple servlet mappins for your JAX-RS implementation.
What you could do is: map RESTEasy to '/'
(or '/api'
for example if your application has other resources to serve and you don't want the JAX-RS part to interfere), then have the following @Path
annotations:
@Path("/public/people")
public interface PeopleService {
// Stuff
}
@Path("/internal/management")
public interface ManagementService {
// Stuff
}
来源:https://stackoverflow.com/questions/20687251/multiple-endpoints-with-resteasy