问题
I have a table:
Table_Name: price_list
---------------------------------------------------
| id | price_type_a | price_type_b | price_type_c |
---------------------------------------------------
| 1 | 1234 | 5678 | 9012 |
| 2 | 3456 | 7890 | 1234 |
| 3 | 5678 | 9012 | 3456 |
---------------------------------------------------
I need a select query in Postgres which gives result like this:
---------------------------
| id | price_type | price |
---------------------------
| 1 | type_a | 1234 |
| 1 | type_b | 5678 |
| 1 | type_c | 9012 |
| 2 | type_a | 3456 |
| 2 | type_b | 7890 |
| 2 | type_c | 1234 |
...
Any help with links to similar examples greatly appreciated.
回答1:
A single SELECT
with a LATERAL
join to a VALUES
expression does the job:
SELECT p.id, v.*
FROM price_list p
, LATERAL (
VALUES
('type_a', p.price_type_a)
, ('type_b', p.price_type_b)
, ('type_c', p.price_type_c)
) v (price_type, price);
Related:
- Convert one row into multiple rows with fewer columns
- SELECT DISTINCT on multiple columns
回答2:
try smth like:
select id, 'type_a',type_a from price_list
union all
select id, 'type_b',type_b from price_list
union all
select id, 'type_c',type_c from price_list
;
update
as a_horse_with_no_name suggests, union is way to select DISTINCT
values, for here would be UNION ALL
prefered - just in case (I don't know if id is UNIQUE)
Of course if it is UK - there will be no difference
来源:https://stackoverflow.com/questions/47077068/postgres-convert-single-row-to-multiple-rows-unpivot