Swift 4 Decodable - Dictionary with enum as key

为君一笑 提交于 2019-12-28 05:19:06

问题


My data structure has an enum as a key, I would expect the below to decode automatically. Is this a bug or some configuration issue?

import Foundation

enum AnEnum: String, Codable {
  case enumValue
}

struct AStruct: Codable {
  let dictionary: [AnEnum: String]
}

let jsonDict = ["dictionary": ["enumValue": "someString"]]
let data = try! JSONSerialization.data(withJSONObject: jsonDict,     options: .prettyPrinted)
let decoder = JSONDecoder()
do {
  try decoder.decode(AStruct.self, from: data)
} catch {
  print(error)
}

The error I get is this, seems to confuse the dict with an array.

typeMismatch(Swift.Array, Swift.DecodingError.Context(codingPath: [Optional(__lldb_expr_85.AStruct.(CodingKeys in _0E2FD0A9B523101D0DCD67578F72D1DD).dictionary)], debugDescription: "Expected to decode Array but found a dictionary instead."))


回答1:


The problem is that Dictionary's Codable conformance can currently only properly handle String and Int keys. For a dictionary with any other Key type (where that Key is Encodable/Decodable), it is encoded and decoded with an unkeyed container (JSON array) with alternating key values.

Therefore when attempting to decode the JSON:

{"dictionary": {"enumValue": "someString"}}

into AStruct, the value for the "dictionary" key is expected to be an array.

So,

let jsonDict = ["dictionary": ["enumValue", "someString"]]

would work, yielding the JSON:

{"dictionary": ["enumValue", "someString"]}

which would then be decoded into:

AStruct(dictionary: [AnEnum.enumValue: "someString"])

However, really I think that Dictionary's Codable conformance should be able to properly deal with any CodingKey conforming type as its Key (which AnEnum can be) – as it can just encode and decode into a keyed container with that key (feel free to file a bug requesting for this).

Until implemented (if at all), we could always build a wrapper type to do this:

struct CodableDictionary<Key : Hashable, Value : Codable> : Codable where Key : CodingKey {

    let decoded: [Key: Value]

    init(_ decoded: [Key: Value]) {
        self.decoded = decoded
    }

    init(from decoder: Decoder) throws {

        let container = try decoder.container(keyedBy: Key.self)

        decoded = Dictionary(uniqueKeysWithValues:
            try container.allKeys.lazy.map {
                (key: $0, value: try container.decode(Value.self, forKey: $0))
            }
        )
    }

    func encode(to encoder: Encoder) throws {

        var container = encoder.container(keyedBy: Key.self)

        for (key, value) in decoded {
            try container.encode(value, forKey: key)
        }
    }
}

and then implement like so:

enum AnEnum : String, CodingKey {
    case enumValue
}

struct AStruct: Codable {

    let dictionary: [AnEnum: String]

    private enum CodingKeys : CodingKey {
        case dictionary
    }

    init(from decoder: Decoder) throws {
        let container = try decoder.container(keyedBy: CodingKeys.self)
        dictionary = try container.decode(CodableDictionary.self, forKey: .dictionary).decoded
    }

    func encode(to encoder: Encoder) throws {
        var container = encoder.container(keyedBy: CodingKeys.self)
        try container.encode(CodableDictionary(dictionary), forKey: .dictionary)
    }
}

(or just have the dictionary property of type CodableDictionary<AnEnum, String> and use the auto-generated Codable conformance – then just speak in terms of dictionary.decoded)

Now we can decode the nested JSON object as expected:

let data = """
{"dictionary": {"enumValue": "someString"}}
""".data(using: .utf8)!

let decoder = JSONDecoder()
do {
    let result = try decoder.decode(AStruct.self, from: data)
    print(result)
} catch {
    print(error)
}

// AStruct(dictionary: [AnEnum.enumValue: "someString"])

Although that all being said, it could be argued that all you're achieving with a dictionary with an enum as a key is just a struct with optional properties (and if you expect a given value to always be there; make it non-optional).

Therefore you may just want your model to look like:

struct BStruct : Codable {
    var enumValue: String?
}

struct AStruct: Codable {

    private enum CodingKeys : String, CodingKey {
        case bStruct = "dictionary"
    }

    let bStruct: BStruct
}

Which would work just fine with your current JSON:

let data = """
{"dictionary": {"enumValue": "someString"}}
""".data(using: .utf8)!

let decoder = JSONDecoder()
do {
    let result = try decoder.decode(AStruct.self, from: data)
    print(result)
} catch {
    print(error)
}

// AStruct(bStruct: BStruct(enumValue: Optional("someString")))



回答2:


In order to solve your problem, you can use one of the two following Playground code snippets.


#1. Using Decodable's init(from:) initializer

import Foundation

enum AnEnum: String, Codable {
    case enumValue
}

struct AStruct {
    enum CodingKeys: String, CodingKey {
        case dictionary
    }
    enum EnumKeys: String, CodingKey {
        case enumValue
    }

    let dictionary: [AnEnum: String]
}

extension AStruct: Decodable {

    init(from decoder: Decoder) throws {
        let container = try decoder.container(keyedBy: CodingKeys.self)
        let dictContainer = try container.nestedContainer(keyedBy: EnumKeys.self, forKey: .dictionary)

        var dictionary = [AnEnum: String]()
        for enumKey in dictContainer.allKeys {
            guard let anEnum = AnEnum(rawValue: enumKey.rawValue) else {
                let context = DecodingError.Context(codingPath: [], debugDescription: "Could not parse json key to an AnEnum object")
                throw DecodingError.dataCorrupted(context)
            }
            let value = try dictContainer.decode(String.self, forKey: enumKey)
            dictionary[anEnum] = value
        }
        self.dictionary = dictionary
    }

}

Usage:

let jsonString = """
{
  "dictionary" : {
    "enumValue" : "someString"
  }
}
"""

let data = jsonString.data(using: String.Encoding.utf8)!
let decoder = JSONDecoder()
let aStruct = try! decoder.decode(AStruct.self, from: data)
dump(aStruct)

/*
 prints:
 ▿ __lldb_expr_148.AStruct
   ▿ dictionary: 1 key/value pair
     ▿ (2 elements)
       - key: __lldb_expr_148.AnEnum.enumValue
       - value: "someString"
 */

#2. Using KeyedDecodingContainerProtocol's decode(_:forKey:) method

import Foundation

public enum AnEnum: String, Codable {
    case enumValue
}

struct AStruct: Decodable {
    enum CodingKeys: String, CodingKey {
        case dictionary
    }

    let dictionary: [AnEnum: String]
}

public extension KeyedDecodingContainer  {

    public func decode(_ type: [AnEnum: String].Type, forKey key: Key) throws -> [AnEnum: String] {
        let stringDictionary = try self.decode([String: String].self, forKey: key)
        var dictionary = [AnEnum: String]()

        for (key, value) in stringDictionary {
            guard let anEnum = AnEnum(rawValue: key) else {
                let context = DecodingError.Context(codingPath: codingPath, debugDescription: "Could not parse json key to an AnEnum object")
                throw DecodingError.dataCorrupted(context)
            }
            dictionary[anEnum] = value
        }

        return dictionary
    }

}

Usage:

let jsonString = """
{
  "dictionary" : {
    "enumValue" : "someString"
  }
}
"""

let data = jsonString.data(using: String.Encoding.utf8)!
let decoder = JSONDecoder()
let aStruct = try! decoder.decode(AStruct.self, from: data)
dump(aStruct)

/*
 prints:
 ▿ __lldb_expr_148.AStruct
   ▿ dictionary: 1 key/value pair
     ▿ (2 elements)
       - key: __lldb_expr_148.AnEnum.enumValue
       - value: "someString"
 */


来源:https://stackoverflow.com/questions/44725202/swift-4-decodable-dictionary-with-enum-as-key

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