问题
How to show the ProgressDialog button after n seconds (fixed) delay that the ProgressDialog is shown?
To be more clear, the ProgressDialog starts normally. How can I show a button within it after n seconds?
L.F.
EDIT
Using the answers of Segi and android_beginner (thank you very much) I'm posting the solution of my problem:
pDialog = new ProgressDialog(mContext);
pDialog.setTitle(Reso.getString(mContext, R.string.waiting));
pDialog.setMessage(Reso.getString(mContext, R.string.waiting));
pDialog.setIndeterminate(true);
pDialog.setCancelable(false);
pDialog.setButton(DialogInterface.BUTTON_NEGATIVE,
Reso.getString(mContext, R.string.annulla),
new DialogInterface.OnClickListener() {
@Override
public void onClick(DialogInterface dialog, int which) {
// Stuff
}
});
pDialog.show();
pDialog.getButton(DialogInterface.BUTTON_NEGATIVE).setVisibility(View.INVISIBLE);
int progressDialogCancelButtonDelay = 2500;
new CountDownTimer(progressDialogCancelButtonDelay, progressDialogCancelButtonDelay + 1) {
@Override public void onTick(long millisUntilFinished) { }
@Override public void onFinish() {
pDialog.getButton(ProgressDialog.BUTTON_NEGATIVE).setVisibility(View.VISIBLE);
}
}.start();
回答1:
Try Something Like Below Code:
ProgressDialog loadingDialog = ProgressDialog.show(activity.this, "", "Loading...",
true, false);
new Thread(new Runnable() {
@Override
public void run() {
try {
Thread.sleep(2500);
runOnUiThread(new Runnable() {
public void run() {
loadingDialog.dismiss();
loadingDialog.setButton(ProgressDialog.BUTTON_NEUTRAL,
"Close",
new DialogInterface.OnClickListener() {
@Override
public void onClick(DialogInterface dialog, int which) {
//button click stuff here
}
});
loadingDialog.show();
loadingDialog.getButton(ProgressDialog.BUTTON_NEUTRAL).setVisibility(View.INVISIBLE);
}
}
});
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}).start();
回答2:
Just extend this class instead of AsyncTask
and be sure to call super()
when appropriate:
public abstract class AsyncTaskWithDelayedIndeterminateProgress
<Params, Progress, Result> extends AsyncTask<Params, Progress, Result> {
private static final int MIN_DELAY = 250;
private final ProgressDialog progressDialog;
private final CountDownTimer countDownTimer;
protected AsyncTaskWithDelayedIndeterminateProgress(Activity activity) {
progressDialog = createProgressDialog(activity);
countDownTimer = createCountDownTimer();
}
@Override protected void onPreExecute() {
countDownTimer.start();
}
@Override protected void onPostExecute(Result children) {
countDownTimer.cancel();
if(progressDialog.isShowing())
progressDialog.dismiss();
}
private ProgressDialog createProgressDialog(Activity activity) {
final ProgressDialog progressDialog = new ProgressDialog(activity);
progressDialog.setIndeterminate(true);
return progressDialog;
}
private CountDownTimer createCountDownTimer() {
return new CountDownTimer(MIN_DELAY, MIN_DELAY + 1) {
@Override public void onTick(long millisUntilFinished) { }
@Override public void onFinish() {
progressDialog.show();
}
};
}
回答3:
make a layout with your ProgressDialog and an invisible button on it. When you show the dialog activate a timer, that set the button visible after n seconds.
I dont know if i understand your question right, but i hope so. =)
来源:https://stackoverflow.com/questions/19358572/how-to-show-progress-dialog-button-dynamically-after-n-seconds-delay