How to compare two dates using UNIX commands [closed]

问题

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Closed 7 years ago.

I have dates like this

Date1="Wed Oct 21 13:05:14 2012"

Date2="Wed Nov 21 12:55:30 2010"

Date3="Wed Nov 21 14:22:30 2012"

How do I find out the latest date?

回答1:

The unix date command can convert date formats, see for example here. So in bash, you'd do something like this:

#!/bin/sh

Date1="Wed Oct 21 13:05:14 2012"
Date2="Wed Nov 21 12:55:30 2010"
Date3="Wed Nov 21 14:22:30 2012"

ts1=`date -d"${Date1}" +%Y%m%d%H%M%S`
ts2=`date -d"${Date2}" +%Y%m%d%H%M%S`
ts3=`date -d"${Date3}" +%Y%m%d%H%M%S`

latest=ts1

if [ $ts2 -gt $ts1 ]; then
    latest=ts2
fi

if [ $ts3 -gt $ts1 ]; then
    latest=ts3
fi

echo "Latest date is ${latest}"

来源：https://stackoverflow.com/questions/13516000/how-to-compare-two-dates-using-unix-commands