问题
I've searched many threads here on removing the first two lines of a string but I can't seem to get it to work with every solution I've tried.
Here is what my string looks like:
version 1.00
6992
[-4.32063, -9.1198, -106.59][0.00064, 0.99993, -0.01210][etc...]
I want to remove the first two lines of this Roblox mesh file for a script I am using. How can I do that?
回答1:
I don't know what your end character is, but what about something like
postString = inputString.split("\n",2)[2];
The end character might need to be escaped, but that is what I would start with.
回答2:
x="""version 1.00
6992
[-4.32063, -9.1198, -106.59][0.00064, 0.99993, -0.01210][etc...]
abc
asdda"""
print "\n".join(x.split("\n")[2:])
You can simply do this.
回答3:
Remove the lines with split
:
lines = """version 1.00
6992
[-4.32063, -9.1198, -106.59][0.00064, 0.99993, -0.01210][etc...]"""
lines = lines.split('\n',2)[-1]
回答4:
You could use some rules, like consider those lines only if they start with '['
character lines = [line for line in lines if line.startswith('[')]
回答5:
I'd rather not split strings in case the string is large, and to maintain newline types afterwards.
Delete the first n lines:
def find_nth(haystack, needle, n):
start = haystack.find(needle)
while start >= 0 and n > 1:
start = haystack.find(needle, start+len(needle))
n -= 1
return start
assert s[find_nth(s, '\n', 2) + 1:] == 'c\nd\n'
See also: Find the nth occurrence of substring in a string
Or to delete just one:
s = 'a\nb\nc\nd\n'
assert s[s.find('\n') + 1:] == 'b\nc\nd\n'
Tested on Python 3.6.6.
回答6:
You can find index of '\n' and ignore first; Then, start new string from end of second '\n' sub-string in main string.
import re
def find_sub_string_index(string, sub_string, offset=0, ignore=0):
start = 0
swap = len(sub_string)
ignore += 1 # find first at least
try:
if start < 0:
return -1 # Not Found
if offset > 0:
# Start main string from offset (offset is begining of check)
string = string[offset:]
for i in range(ignore):
# swap: end of substring index
# start is end of sub-string index in main string
start += re.search(sub_string, string).start() + swap
string = string[start:]
return start
except:
return -1 # Got Error
string = """The first line.
The second line.
The third line.
The forth line.
The fifth line."""
sub_string = "\n"
ignore = 1 # Ignore times
start = find_sub_string_index(string, sub_string, ignore=1)
print("Finding sub-string '{0}' from main text.".format(sub_string))
print("Ignore {0} times.".format(ignore))
print("Start index:", start)
print("Result:")
print(string[start:])
The result is:
$ python3 test.py
Finding sub-string '
' from main text.
Ignore 1 times.
Start index: 33
Result:
The third line.
The forth line.
The fifth line.
$
$
$
$ python3 test.py
Finding sub-string 'The' from main text.
Ignore 2 times.
Start index: 19
Result:
second line.
The third line.
The forth line.
The fifth line.
$
来源:https://stackoverflow.com/questions/30833409/python-deleting-the-first-2-lines-of-a-string