问题
I would like to use a MutationObserver object to observe changes to some of my DOM nodes.
The docs give an example of creating a MutationObserver
object and registering it on a target.
// select the target node
var target = document.querySelector('#some-id');
// create an observer instance
var observer = new MutationObserver(function(mutations) {
mutations.forEach(function(mutation) {
console.log(mutation.type);
});
});
// configuration of the observer:
var config = { attributes: true, childList: true, characterData: true };
// pass in the target node, as well as the observer options
observer.observe(target, config);
Say I have the code above, but just under it, I place this code:
var target2 = document.querySelector('#some-other-id');
var config2 = {attributes: true, subtree: true};
observer.observe(target2, config2);
Will observer
:
- now be observing 2 targets?
- will it stop observing
target
? - will it decide not to observe
target2
? - will it throw an error?
- or will it exhibit some other behavior?
回答1:
The observer will now be watching two targets - target
and target2
per your definitions. No error will be thrown, and target
will not be "unregistered" in favor of target2
. No unexpected or other behaviors will be exhibited.
Here is a sample which uses the same MutationObserver
on two contenteditable elements. To view this, delete the <span>
node from each contenteditable
element and view the behavior span across both observed elements.
<div id="myTextArea" contenteditable="true">
<span contenteditable="false">Span A</span>
</div>
<div id="myTextArea2" contenteditable="true">
<span contenteditable="false">Span B</span>
</div>
var observer = new MutationObserver(function(mutations) {
mutations.forEach(function(mutation) {
//console.log($(mutation.removedNodes)); // <<-- includes text nodes
$(mutation.removedNodes).each(function(value, index) {
if(this.nodeType === 1) {
console.log(this)
}
});
});
});
var config = { attributes: true, childList: true, characterData: true };
observer.observe($('#myTextArea')[0], config);
observer.observe($('#myTextArea2')[0], config);
JSFiddle Link - demo
Note that I have recycled the same config for this first demo, but, placing a new config will be exclusive to that observed element. Taking your example as defined in config2
, if used on #myTextArea2
, you'll not see the logged node per the configuration options, but notice that the observer for #myTextArea
is unaffected.
JSFiddle Link - demo - configuration exclusiveness
来源:https://stackoverflow.com/questions/30807846/can-a-single-mutationobserver-object-observe-multiple-targets