Convert String to Joda LocalTime format (HH:mm:ss) and Remove milliseconds

问题

DateTimeFormatter fmt = DateTimeFormat.forPattern("HH:mm:ss");
LocalTime localTime = fmt.parseLocalTime("02:51:20");
System.out.println("LocalTime:            "+localTime);

I need only 02:51:20 but it outputs as 02:51:20.000. Is there any way that I can remove the .000 (milliseconds) from the output.

回答1:

Yes - you just need to format when you print out. Currently you're just using the default toString() representation. If you're happy with the formatter you've already got, you can just use:

System.out.println("LocalTime:            " + fmt.print(localTime));

回答2:

You can easily use your DateTimeFormetter print() method. Try like this;

    DateTimeFormatter fmt = DateTimeFormat.forPattern("HH:mm:ss");
    LocalTime localTime = fmt.parseLocalTime("02:51:20");
    System.out.println("LocalTime                        :  " + localTime);
    System.out.println("LocalTime with DateTimeFormatter :  " + fmt.print(localTime));

And the output is;

LocalTime                        :  02:51:20.000
LocalTime with DateTimeFormatter :  02:51:20

回答3:

Fixed this using

DateTime time = new DateTime();
DateTimeFormatter format = DateTimeFormat.forPattern("HH:mm:ss");
String localTime = time != null ? format.print(new LocalTime(time.getHourOfDay(), 
time.getMinuteOfHour(), time.getSecondOfMinute())) : null;

DateTime and LocalTime are from joda

来源：https://stackoverflow.com/questions/27989498/convert-string-to-joda-localtime-format-hhmmss-and-remove-milliseconds