How to implement __isset() magic method in PHP?

你。 提交于 2019-12-19 05:22:20

问题


I'm trying to make functions like empty() and isset() work with data returned by methods.

What I have so far:

abstract class FooBase{

  public function __isset($name){
    $getter = 'get'.ucfirst($name);
    if(method_exists($this, $getter))
      return isset($this->$getter()); // not working :(
      // Fatal error: Can't use method return value in write context 
  }

  public function __get($name){
    $getter = 'get'.ucfirst($name);
    if(method_exists($this, $getter))
      return $this->$getter();
  }

  public function __set($name, $value){
    $setter = 'set'.ucfirst($name);
    if(method_exists($this, $setter))
      return $this->$setter($value);
  }

  public function __call($name, $arguments){
    $caller = 'call'.ucfirst($name);
    if(method_exists($this, $caller)) return $this->$caller($arguments);   
  }

}

the usage:

class Foo extends FooBase{
  private $my_stuff;

  public function getStuff(){
    return $this->my_stuff;
  }

  public function setStuff($stuff){
    $this->my_stuff = $stuff;
  }
}


$foo = new Foo();

if(empty($foo->stuff)) echo "empty() works! \n"; else "empty() doesn't work:( \n";
$foo->stuff = 'something';
if(empty($foo->stuff)) echo "empty() doesn't work:( \n"; else "empty() works! \n";

http://codepad.org/QuPNLYXP

How can I make it so empty/isset return true/false if:

  • my_stuff above is not set, or has a empty or zero value in case of empty()
  • the method doesn't exist (not sure if neeed, because I think you get a fatal error anyway)

?


回答1:


public function __isset($name){
    $getter = 'get'.ucfirst($name);
    return method_exists($this, $getter) && !is_null($this->$getter());
}

This check whether or not $getter() exists (if it does not exist, it's assumed that the property also does not exist) and returns a non-null value. So NULL will cause it to return false, as you would expect after reading the php manual for isset().




回答2:


A bit more option not to depend on getter

public function __isset($name)
{
    $getter = 'get' . ucfirst($name);
    if (method_exists($this, $getter)) {
        return !is_null($this->$getter());
    } else {
        return isset($this->$name);
    }
}



回答3:


Your code returns error because of these lines:

if(method_exists($this, $getter))
return isset($this->$getter());

You can just replace it with:

if (!method_exists($this), $getter) {
    return false; // method does not exist, assume no property
}
$getter_result = $this->$getter();
return isset($getter_result);

and it will return false if the getter is not defined or it returns NULL. I propose you should better think of the way you determine some property is set or not.

The above code is also assuming that you are creating getters for all of your properties, thus when there is no getter, the property is assumed as not set.

Also, why are you using getters? They seem to be some overkill here.



来源:https://stackoverflow.com/questions/6242591/how-to-implement-isset-magic-method-in-php

易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!