Get last three digits of an integer

问题

I wish to change an integer such as 23457689 to 689, 12457245 to 245 etc.

I do not require the numbers to be rounded and do not wish to have to convert to String.

Any ideas how this can be done in Python 2.7?

回答1:

Use the % operation:

>>> x = 23457689
>>> x % 1000
689

% is the mod (i.e. modulo) operation.

回答2:

To handle both positive and negative integers correctly:

>>> x = -23457689
>>> print abs(x) % 1000
689

As a function where you can select the number of leading digits to keep:

import math
def extract_digits(integer, digits=3, keep_sign=False):
    sign = 1 if not keep_sign else int(math.copysign(1, integer))
    return abs(integer) % (10**digits) * sign

The constraint to avoid converting to str is too pedantic. Converting to str would be a good way to do this if the format of the number might change or if the format of the trailing digits that need to be kept will change.

>>> int(str(x)[-3:])
              ^^^^^ Easier to modify this than shoe-horning the mod function.

来源：https://stackoverflow.com/questions/28570505/get-last-three-digits-of-an-integer