问题
Here Matrix multiplication using hdf5 I use hdf5 (pytables) for big matrix multiplication, but I was suprised because using hdf5 it works even faster then using plain numpy.dot and store matrices in RAM, what is the reason of this behavior?
And maybe there is some faster function for matrix multiplication in python, because I still use numpy.dot for small block matrix multiplication.
here is some code:
Assume matrices can fit in RAM: test on matrix 10*1000 x 1000.
Using default numpy(I think no BLAS lib). Plain numpy arrays are in RAM: time 9.48
If A,B in RAM, C on disk: time 1.48
If A,B,C on disk: time 372.25
If I use numpy with MKL results are: 0.15,0.45,43.5.
Results looks reasonable, but I still don't understand why in 1st case block multiplication is faster(when we store A,B in RAM).
n_row=1000
n_col=1000
n_batch=10
def test_plain_numpy():
A=np.random.rand(n_row,n_col)# float by default?
B=np.random.rand(n_col,n_row)
t0= time.time()
res= np.dot(A,B)
print (time.time()-t0)
#A,B in RAM, C on disk
def test_hdf5_ram():
rows = n_row
cols = n_col
batches = n_batch
#using numpy array
A=np.random.rand(n_row,n_col)
B=np.random.rand(n_col,n_row)
#settings for all hdf5 files
atom = tables.Float32Atom() #if store uint8 less memory?
filters = tables.Filters(complevel=9, complib='blosc') # tune parameters
Nchunk = 128 # ?
chunkshape = (Nchunk, Nchunk)
chunk_multiple = 1
block_size = chunk_multiple * Nchunk
#using hdf5
fileName_C = 'CArray_C.h5'
shape = (A.shape[0], B.shape[1])
h5f_C = tables.open_file(fileName_C, 'w')
C = h5f_C.create_carray(h5f_C.root, 'CArray', atom, shape, chunkshape=chunkshape, filters=filters)
sz= block_size
t0= time.time()
for i in range(0, A.shape[0], sz):
for j in range(0, B.shape[1], sz):
for k in range(0, A.shape[1], sz):
C[i:i+sz,j:j+sz] += np.dot(A[i:i+sz,k:k+sz],B[k:k+sz,j:j+sz])
print (time.time()-t0)
h5f_C.close()
def test_hdf5_disk():
rows = n_row
cols = n_col
batches = n_batch
#settings for all hdf5 files
atom = tables.Float32Atom() #if store uint8 less memory?
filters = tables.Filters(complevel=9, complib='blosc') # tune parameters
Nchunk = 128 # ?
chunkshape = (Nchunk, Nchunk)
chunk_multiple = 1
block_size = chunk_multiple * Nchunk
fileName_A = 'carray_A.h5'
shape_A = (n_row*n_batch, n_col) # predefined size
h5f_A = tables.open_file(fileName_A, 'w')
A = h5f_A.create_carray(h5f_A.root, 'CArray', atom, shape_A, chunkshape=chunkshape, filters=filters)
for i in range(batches):
data = np.random.rand(n_row, n_col)
A[i*n_row:(i+1)*n_row]= data[:]
rows = n_col
cols = n_row
batches = n_batch
fileName_B = 'carray_B.h5'
shape_B = (rows, cols*batches) # predefined size
h5f_B = tables.open_file(fileName_B, 'w')
B = h5f_B.create_carray(h5f_B.root, 'CArray', atom, shape_B, chunkshape=chunkshape, filters=filters)
sz= rows/batches
for i in range(batches):
data = np.random.rand(sz, cols*batches)
B[i*sz:(i+1)*sz]= data[:]
fileName_C = 'CArray_C.h5'
shape = (A.shape[0], B.shape[1])
h5f_C = tables.open_file(fileName_C, 'w')
C = h5f_C.create_carray(h5f_C.root, 'CArray', atom, shape, chunkshape=chunkshape, filters=filters)
sz= block_size
t0= time.time()
for i in range(0, A.shape[0], sz):
for j in range(0, B.shape[1], sz):
for k in range(0, A.shape[1], sz):
C[i:i+sz,j:j+sz] += np.dot(A[i:i+sz,k:k+sz],B[k:k+sz,j:j+sz])
print (time.time()-t0)
h5f_A.close()
h5f_B.close()
h5f_C.close()
回答1:
np.dot
dispatches to BLAS when
- NumPy has been compiled to use BLAS,
- a BLAS implementation is available at run-time,
- your data has one of the dtypes
float32
,float64
,complex32
orcomplex64
, and - the data is suitably aligned in memory.
Otherwise, it defaults to using its own, slow, matrix multiplication routine.
Checking your BLAS linkage is described here. In short, check whether there's a file _dotblas.so
or similar in your NumPy installation. When there is, check which BLAS library it's linked against; the reference BLAS is slow, ATLAS is fast, OpenBLAS and vendor-specific versions such as Intel MKL are even faster. Watch out with multithreaded BLAS implementations as they don't play nicely with Python's multiprocessing
.
Next, check your data alignment by inspecting the flags
of your arrays. In versions of NumPy before 1.7.2, both arguments to np.dot
should be C-ordered. In NumPy >= 1.7.2, this doesn't matter as much anymore as special cases for Fortran arrays have been introduced.
>>> X = np.random.randn(10, 4)
>>> Y = np.random.randn(7, 4).T
>>> X.flags
C_CONTIGUOUS : True
F_CONTIGUOUS : False
OWNDATA : True
WRITEABLE : True
ALIGNED : True
UPDATEIFCOPY : False
>>> Y.flags
C_CONTIGUOUS : False
F_CONTIGUOUS : True
OWNDATA : False
WRITEABLE : True
ALIGNED : True
UPDATEIFCOPY : False
If your NumPy is not linked against BLAS, either (easy) re-install it, or (hard) use the BLAS gemm
(generalized matrix multiply) function from SciPy:
>>> from scipy.linalg import get_blas_funcs
>>> gemm = get_blas_funcs("gemm", [X, Y])
>>> np.all(gemm(1, X, Y) == np.dot(X, Y))
True
This looks easy, but it does hardly any error checking, so you must really know what you're doing.
来源:https://stackoverflow.com/questions/19839539/how-to-get-faster-code-than-numpy-dot-for-matrix-multiplication