join one row to all row and returning all row

青春壹個敷衍的年華 提交于 2019-12-14 03:25:25

问题


can I get data like this from my table

| id_outlet| date       |  count(msisdn) |  
| 34.10.1  |  2014-08   |      0         |
| 34.10.1  |  2014-09   |      3         |
| 34.10.1  |  2014-10   |      2         |
| 34.10.2  |  2014-08   |      1         |
| 34.10.2  |  2014-09   |      0         |
| 34.10.2  |  2014-10   |      0         |  

So I have 2 tables
1. table outlet (unique)
2. table sales (detail of table outlet)
As u see in my second table there are 3 periode (2014-08, 2014-09, 2014-10)
I want join that periode with id_outlet in first table like that example.
Can I?
Please Help me


回答1:


Using a CROSS JOIN:-

SELECT
    o.id_outlet,
    s_main.periode,
    o.branch, 
    count(msisdn)
FROM
(
    SELECT DISTINCT SUBSTRING(date,1,7) AS periode
    FROM sales
) s_main 
CROSS JOIN outlet o
LEFT OUTER JOIN sales s
ON s_main.periode = SUBSTRING(s.date,1,7)
AND o.id_outlet = s.id_outlet
WHERE (o.STATUS LIKE 'STREET%')
GROUP BY s_main.periode, o.branch, o.id_outlet

If you have a table of dates then you can just use that rather than the sub query to get the dates (which also avoids the potential problem of not having a date in the results for a month where there has been zero sales for any outlet).




回答2:


Don't worry, be happy!

SELECT
    o.id_outlet,
    SUBSTRING(s.date,1,7) AS periode,
    o.branch 
FROM outlet o LEFT JOIN sales s ON o.id_outlet = s.id_outlet
WHERE (o.STATUS LIKE 'STREET%')
ORDER BY o.id_outlet, YEAR(s.DATE), MONTH(s.DATE), branch



回答3:


You need this query:

SELECT
    o.id_outlet,
    d.period AS periode,
    o.branch,
    count(msisdn)
FROM dates d LEFT JOIN outlet o ON d.period = SUBSTRING(o.date,1,7) LEFT JOIN sales s ON o.id_outlet = s.id_outlet
WHERE (o.STATUS LIKE 'STREET%')
GROUP BY CONCAT(d.period, '@', s.id_outlet)
ORDER BY o.id_outlet, d.period, branch


来源:https://stackoverflow.com/questions/26521416/join-one-row-to-all-row-and-returning-all-row

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