问题
My actual data is as follows :
<image name="101272.dcm">
<gobject type="Right"><polyline><vertex index="0" t="0.0" x="636.0" y="1920.0" z="0.0"/><vertex index="1" t="0.0" x="604.0" y="2296.0" z="0.0"/></polyline></gobject>
</image>
<image name="101280.dcm">
<gobject type="Right"><polyline><vertex index="0" t="0.0" x="1776.0" y="392.0" z="0.0"/><vertex index="1" t="0.0" x="1456.0" y="424.0" z="0.0"/></polyline></gobject>
</image>
I was successful in extracting all other data as required. But using the comma as delimiter is painful as Im a beginner in xslt.
Im using xslt version 2 and my code is :
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="/">
seriesUID,annotationType,coordSys,data,name,label
<xsl:for-each select="//gobject">
<xsl:variable name="seriesUID" select="ancestor::image/@name"/>
<xsl:value-of select="substring-before($seriesUID,'.dcm')"/>
<xsl:value-of select="concat(',','polygon')"/>
<xsl:value-of select="@annotationType"/>
<xsl:value-of select="concat(',','Image')"/>
<xsl:value-of select="@coordSys"/>
<xsl:value-of select="concat(',','[')"/>
<xsl:for-each select="polyline/vertex">
<xsl:value-of select="concat('','[')"/>
<xsl:value-of select="@x"/>
<xsl:value-of select="@y"/>
<xsl:value-of select="@z"/>
<xsl:value-of select="concat(']','')"/>
</xsl:for-each>
<xsl:value-of select="concat(']','',',')"/>
<xsl:value-of select="@type"/>
<xsl:value-of select="concat(',','')"/>
<xsl:value-of select="@label"/>
<xsl:value-of select="concat(',','
')"/>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
Generating below output :
seriesUID annotationType coordSys data name label
1006780 polygon Image ["[3476.0,1196.0,0.0],"[3436.0,1036.0,0.0],] Right
1006810 polygon Image ["[3064.0,744.0,0.0],"[3300.0,912.0,0.0],] Right
Please help me eliminate the double quote marks and the last COMMA in the field data.
回答1:
If you can only use XSLT 2.0, then this is how you could do it...
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0">
<xsl:output method="text" />
<xsl:template match="/">
<xsl:text>type,data,label </xsl:text>
<xsl:apply-templates select="//parent" />
</xsl:template>
<xsl:template match="parent">
<xsl:value-of select="@type" />
<xsl:text>,"[</xsl:text>
<xsl:value-of select="child1/child2/concat('[',@x,',',@y,',',@z,']')" separator="," />
<xsl:text>]",hard coded </xsl:text>
</xsl:template>
</xsl:stylesheet>
EDIT: I am wondering if indeed you are using XSLT 2.0. Simply putting version="2.0"
in a stylesheet won't achieve anything unless you have an XSLT processor that supports it.
If this is the case, here is an XSLT 1.0 version of the previous XSLT
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0">
<xsl:output method="text" />
<xsl:template match="/">
<xsl:text>type,data,label </xsl:text>
<xsl:apply-templates select="//parent" />
</xsl:template>
<xsl:template match="parent">
<xsl:value-of select="@type" />
<xsl:text>,"[</xsl:text>
<xsl:for-each select="child1/child2">
<xsl:if test="position() > 1">,</xsl:if>
<xsl:value-of select="concat('[',@x,',',@y,',',@z,']')" />
</xsl:for-each>
<xsl:text>]",hard coded </xsl:text>
</xsl:template>
</xsl:stylesheet>
You should be able to adapt this to your new XML hopefully.
Note: To see what XSLT processor and version you actually have, see this question...
How can I check which XSLT processor is being used in Solr?
来源:https://stackoverflow.com/questions/50593998/add-comma-as-delimiter-when-creating-array-of-arrays-as-one-field-in-csv-from-xm